Jeksisososososodododo 5+2
2 answers:
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Hello there!
The formula to find the area of a trapezoid is:
A =
Since we have everything, we just plug them in :)
A =
A = (3x+3x+4)/2 (x) + (3x+3x+4)/2 (2)
A= <span><span><span><span>3x^2</span>+<span>2x</span></span>+<span>6x</span></span>+<span>4
A = </span></span><span>3x^2+8x+4
The correct answer is option A
I hope I helped!
Please feel free to ask me any additional questions about the answer.
</span>
The formula to find the area of a trapezoid is:
A =
Since we have everything, we just plug them in :)
A =
A = (3x+3x+4)/2 (x) + (3x+3x+4)/2 (2)
A= <span><span><span><span>3x^2</span>+<span>2x</span></span>+<span>6x</span></span>+<span>4
A = </span></span><span>3x^2+8x+4
The correct answer is option A
I hope I helped!
Please feel free to ask me any additional questions about the answer.
</span>
Answer:
a) s = -16 + 192t + 96
b) Height of the football after 2 seconds is 448 feet.
ii. The football would not hit the ground after 2 seconds.
Step-by-step explanation:
Given:
s = -16 +
t +
where: s is the height of the football above the ground, t is the time, is the initial velocity and
is the initial height.
The height of the building = = 192 feet and the initial speed of the ball =
= 96 feet per second, then;
s = -16 + 192t + 96
a) The polynomial is given as:
s = -16 + 192t + 96
b) The height of the football when t = 2 seconds is;
s = -16(2) + 192(2) + 96
= -32 + 384 + 96
= -32 + 480
s = 448
The height of the football when t = 2 seconds is 448 feet.
ii. The football would not hit the ground after 2 seconds.