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Basile [38]
3 years ago
14

How many more miles is 27.2 than 6.8

Mathematics
2 answers:
Lina20 [59]3 years ago
8 0

Answer: 20.4

Step-by-step explanation:<em><u> How many more</u></em> miles is <em>27.2</em> <em><u>than</u></em><em> 6.8</em>

usually these kind of equations mean to subtract, in other terms find the underlined key words

27.2-6.8= 20.4

Anna71 [15]3 years ago
7 0

Answer:

20.4 miles

Step-by-step explanation:

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Which inequality statement describes the two numbers: -13 and a number 28 units to the right of -13?
kkurt [141]
So you have -13, then a number that's somewhere to the right of -13. imagine a number line: the negative values are on the left side of the zero, the positive values are on the right. if you're moving to the RIGHT of -13, that means that the value will be greater than -13, or in other words, -13 will be less than the new value because you moved right.

to find the number 28 units to the right of -13, you simply need to add these two numbers: -13 + 28. you add them because you're moving 28 units in the POSITIVE direction, aka you're going UP, so you want to add. -13 + 28 = 15.

now read the statements your question gave you. C and D are just straight-up false--a positive number is never less than a negative number. those are out immediately. now, the numbers you're working with are -13 and 15, so you can immediately ignore B as an answer choice, but still: A is correct because it shows the correct inequality. -13 is less than the number 28 units to the right of it, that number being positive 15.
7 0
3 years ago
Read 2 more answers
Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
3 years ago
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Prove This :<br><br>sin(A+B)+sin(A−B)=2sinA⋅cosB​
MaRussiya [10]

Answer:

We know

sin (A + B) = sin A cos B + cos A sin B

sin (A - B) = sin A cos B - cos A sin B

(A + B) + sin (A - B)

= sin A cos B + cos A sin B + sin A cos B - cos A sin B

= sin A cos B + sin A cos B

= 2 sin A cos B

3 0
3 years ago
Solve |2x – 6| = 4x+4
Novay_Z [31]

Answer:

-6-4=4x-2x

10=2x

x=2÷10

x=5

6 0
3 years ago
Read 2 more answers
PLEASE pLEASE HELP!!!!!!!!
sleet_krkn [62]

Answer: B = 73

Step-by-step explanation:

Since A = 17 degrees and there's already a right angle (90 degrees)

They add up to 107 degrees meaning the last angle is 73 because

the sum of interior angles add up to 180.

I'm sorry I couldn't find the other ones ( I don't have time )

but I'll give you a hint. You'll need to use Sine, Cosine, or Tangent

3 0
3 years ago
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