The value of RS in the line segment is 20
To solve for RS :
From the line segment attached :
The information given is :
RS = 3x - 16
ST = 4x - 8
RT = 60
RT = RS + ST
60 = 3x - 16 + 4x - 8
60 = 7x - 24
60 + 24 = 7x
84 = 7x
Divide both sides by 7
84/7 = x
x = 12
RS = 3x - 16
RS = 3(12) - 16
RS = 36 - 16
RS = 20
HENCE, RS = 20
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the answer would be 9999.01
I think it’s A and B because on the top where is is 24 is M and the bottom is 25 which is L
Answer:
b and d
Step-by-step explanation:
hope it helped
The elimination method works by adding the two equations and eliminating one variable. Then you solve an equation in one variable. Finally, you use substitution or elimination again to find the other variable. Sometimes, by simply adding the equations, a variable is not eliminated. Then you need to multiply one or both equations by a factor to get a variable to be eliminated.
A)
2x - 4y = 8
x + 3y = -11
Adding the equations does not eliminate x or y.
Notice that in the first equation, every coefficient is even. We can divide both sides of the first equation by 2. Then the first term would be x. Instead, let's divide both sides of the first equation by -2. Then the x's will be eliminated.
-x + 2y = -4 <-- The first equation divided by -2
x + 3y = -11 <-- The original second equation. Now we add the equations.
----------------
5y = -15
y = -3
Now that we know y = -3, we substitute it into the first original equation and solve for x.
2x - 4y = 8
2x - 4(-3) = 8
2x + 12 = 8
2x = -4
x = -2
Answer: x = -2; y = -3
B)
We see that the x's will be eliminated by addition. Just add the equations.
-3x + 7y = 9
3x - 7y = 1
---------------
0 + 0 = 10
0 = 10 <---- this is a false statement, so this system of equations has no solution.
