I believe the answer is C - 60 inches. 60 x 2 = 120, which is both lengths, and since he width is half the length, then 30 x 2 = 60. So 130 (length) + 60 (width) = 180. So 60 inches would be the maximum length for both sides.
Answer:
ikik
Step-by-step explanation:
just need points sorry
The first thing you should do is solve the equation yourself.
1) Distribute the 2.
6x + 4 = 2x – 16
2) Next, you'll want to get the x's on one side. So add -2x to both sides.
6x + 4 + -2x = 2x + -2x - 16
4x + 4 = -16
3) Now subtract 4 from both sides
4x + 4 – 4 = -16 – 4
4x = -12
4) Finally, divide both sides by 4
4x/4 = -12/4
x = –3
To solve this problem all you need to do is look back out you work, and figure out the correct solution. The answer the question is The student made an error in Step 1.
Answer:
The graph in the attached figure
Step-by-step explanation:
we have

Remember that the denominator cannot be equal to zero
so
The value of x cannot be equal to x=-2
<em>Simplify the numerator</em>
----> by difference of squares
substitute

simplify

The domain is all real numbers except the value of x=-2
The y-intercept is the point (0,-6) ---> value of y when the value of x is equal to zero)
The x-intercept is the point (2,0) ---> value of x when the value of y is equal to zero)
therefore
The graph in the attached figure
The perimeter of right isosceles ΔABC with midsegment DE is 16 + 8√2.
If right isosceles ΔABC has hypotenuse length h, then the two other sides are congruent.
side a = side b
Using Pythagorean theorem, c^2 = a^2 + b^2
h^2 = a^2 + b^2 a = b
h^2 = 2a^2
a = h/√2
If DE is a midsegment not parallel to the hypotenuse, then it is a segment that connects the midpoints of one side of a triangle and the hypotenuse. See photo for reference.
ΔABC and ΔADE are similar triangles.
a : b : h = a/2 : 4 : h/2
If a/2 = a/2, then b/2 = 4.
b/2 = 4
b = 8
If a = b, then a = 8.
If a = h/√2, then
8 = h/√2
h = 8√2
Solving for the perimeter,
P = a + b + h
P = 8 + 8 + 8√2
P = 16 + 8√2
P = 27.3137085
To learn more about midsegment: brainly.com/question/7423948
#SPJ4