Answer: D) Intersecting, but not perpendicular lines
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Explanation:
Let's solve the second equation for y
2x - 12y = 24
-12y = 24-2x ................... subtract 2x from both sides
-12y = -2x+24
y = (-2x+24)/(-12) ............ divide both sides by -12
y = (-2x)/(-12) + 24/(-12)
y = (1/6)x - 2
The slope here is 1/6 since the last equation is in y = mx+b form.
The slope of y = 6x-2 is 6
Multiplying the two slopes leads to (1/6)*(6) = 1. Since the result is not -1, this means the lines are not perpendicular.
The lines aren't parallel either because we would need to have the two slopes be equal. Parallel lines have equal slopes but different y intercepts.
Therefore, we consider these lines to be intersecting, but not perpendicular. The single point they intersect at is the solution to the system.
