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ira [324]
3 years ago
5

Helpit said line on the last one plz and its due today ​

Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0

Answer: D) Intersecting, but not perpendicular lines

===============================================================

Explanation:

Let's solve the second equation for y

2x - 12y = 24

-12y = 24-2x ................... subtract 2x from both sides

-12y = -2x+24

y = (-2x+24)/(-12) ............ divide both sides by -12

y = (-2x)/(-12) + 24/(-12)

y = (1/6)x - 2

The slope here is 1/6 since the last equation is in y = mx+b form.

The slope of y = 6x-2 is 6

Multiplying the two slopes leads to (1/6)*(6) = 1. Since the result is not -1, this means the lines are not perpendicular.

The lines aren't parallel either because we would need to have the two slopes be equal. Parallel lines have equal slopes but different y intercepts.

Therefore, we consider these lines to be intersecting, but not perpendicular.  The single point they intersect at is the solution to the system.

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