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IgorC [24]
3 years ago
13

Please please help me!!

Mathematics
2 answers:
Deffense [45]3 years ago
8 0

Answer:

(-3,1.5)

Step-by-step explanation:

AURORKA [14]3 years ago
6 0

Answer:

Best estimate would be (-3 , 1.5)

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1. Which is an equation of the line with slope 4 and a y-intercept -3? Ay = -3x + 4 By = -3x + + C y = 4x -3 D y = 4x 3 4​
Neporo4naja [7]
The correct answer for this questions it’s letter C
3 0
4 years ago
Can Somebody Solve This ? (Show Work!)
77julia77 [94]

Answer:

x<7

Step-by-step explanation:

4(5−2x)−3x>8x−113

−11x+20>8x−113

−11x+20−8x>8x−113−8x

−19x+20>−113

       -20    -20

-19x>-113

/-19    /-19

(flip the sign)

x<7

i can't do the greater than or equal to sign so just remember to add that in :)

5 0
4 years ago
Don't guess!
MrRissso [65]

Answer:

C

Step-by-step explanation:

1. Plug 7/8 into the expression:

4(7/8)

2. Multiply:

4 * 7/8 = 28/8 = 3.5

3.5 < 4

7 0
3 years ago
Read 2 more answers
Jim's Camera shop sells two high-end cameras, the Sky Eagle and Horizon. The demands for these two cameras are as follows: DS =
BartSMP [9]

The revenue is given by the product of the price and the demand function

  • The revenue function for Sky Eagle is <u>RS = 229·PS - 0.60·PS² + 0.35·PS·PH</u>.
  • The revenue function for Horizon is <u>RH = 269·PH + 0.10·PS·PH - 0.64·PH²</u>.

Reasons:

The given parameters are;

The demand function for the Sky Eagle, DS = 229 - 0.60·PS + 0.35·PH

The demand function for the Horizon, DH = 269 + 0.10·PS - 0.64·PH

The above demand functions gives the quantity demanded

Therefore, the revenue function is given by the product of the price and the demand function as follows;

RS = PS × DS = PS × (229 - 0.60·PS + 0.35·PH) = 229·PS - 0.60·PS² + 0.35·PS·PH

The revenue for Sky Eagle <u>RS = 229·PS - 0.60·PS² + 0.35·PS·PH</u>

<u />

Revenue for Horizon is found as follows;

RH = PH ×(269 + 0.10·PS - 0.64·PH) = 269·PH + 0.10·PS·PH - 0.64·PH²

The revenue for Horizon, <u>RH =  269·PH + 0.10·PS·PH - 0.64·PH²</u>

Learn more demand function here:

brainly.com/question/16888880

5 0
3 years ago
You are to run a conduit diagonally across a parking lot that is 200 ft long and 60 ft wide. How much conduit will you need to c
torisob [31]

Answer:209ft

Step-by-step explanation:

We let y be the unknown value, which is length of conduit.

200^2 + 60^2=y^2

40000 + 3600=y^2

43600=y^2

Square both side

y= sqrt(43600)

y= 208.8061 ft

y=209 ft

3 0
3 years ago
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