This is a problem of Permutations. We have 3 cases depending on the number of B's. Since no more than three B's can be used we can use either one, two or three B's at a time.
Case 1: Five A's and One B
Total number of letters = 6
Total number of words possible = 
Case 2: Five A's and Two B's
Total number of letters = 7
Total number of words possible = 
Case 3: Five A's and Three B's
Total number of letters = 8
Total number of words possible = 
Total number of possible words will be the sum of all three cases.
Therefore, the total number of words that can be written using exactly five A's and no more than three B's (and no other letters) are 6 + 21 + 56 = 83
Okay well then this gotta be more then 8 points
Step-by-step explanation:
Given,
AC=AD and ang CBA = ang BAD
To prove : Triangle ABC is congruent to Triangle ABD
Proof
Statements Reasons
1. In triangle ABC and 1.
Triangle ABD
i) AC = AD (S) i) Given
ii)ang CAB=ang BAD (A) ii) Given
iii) AB = AB (S) iii)common sides
2. Triangle ABC is
Congurent to triangle
ABD
2. From SAS fact
D the last one because it simplify by y^3/x^18