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3 years ago

...........................................,

Mathematics

1 answer:

irakobra [83]3 years ago

6 0

Answer:

.____. whale there be no question here?

Step-by-step explanation:

.___. whale is always the answer

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6. Suppose that a fair coin is tossed 2 times, and the result of each toss (H or T) is recorded.

nekit [7.7K]

Answer:

a) $S= {HH, HT, TH, TT}$

b) $P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25$

$P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5$

$P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25$

And we have the following table:

X | 0 | 1 | 2

P(X) | 0.25 | 0.5 | 0.25

Step-by-step explanation:

Let's define first some notation

H= represent a head for the coin tossed

T= represent tails for the coin tossed

We are going to toss a coin 2 times so then the size of the sample size is $2^2 = 4$

a. What is the sample space for this chance experiment?

The sampling space on this case is given by:

$S= {HH, HT, TH, TT}$

b. For this chance experiment, give the probability distribution for the random variable of the total number of heads observed.

The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:

$P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25$

$P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5$

$P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25$

And we have the following table:

X | 0 | 1 | 2

P(X) | 0.25 | 0.5 | 0.25

5 0

3 years ago

Can u help me plz and thank you

Alenkinab [10]

The number is 2 :) because you need common denominators therefore you multiply by 3 so that 4 becomes 14 therefore 3 times 2 is 6 and 11 menus 6 is 4 so you get 4/14

4 0

4 years ago

Please need help on this

umka2103 [35]

A "solution" is where the graph crosses the
x-axis so while the quadratic has no real solutions, the straight line passing through it does as it intersects the x-axis at x=-2.
Hope this helps! :)

6 0

4 years ago

NO LINKS!! Please help me with this problem

12345 [234]

Answer:

$\frac{x^2}{784}+\frac{y^2}{400}=1$

Step-by-step explanation:

Horizontal Major Axis:

$\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}$

Vertical Major Axis:

$\frac{(y-k)^2}{a^2}+\frac{(x-h)^2}{b^2}+$

So these two expressions are essentially the same with the only difference being the location of "a" and "b". The length of the major axis will be "2a" and the length of the minor axis will be "2b". The way I remember this is because when you have the horizontal major axis the "a" value is in the denominator of the (x-h) and I think of "x" as a horizontal value, since it moves a point horizontally. When you have a vertical major axis the "a" value is in the denominator of (y-k) and I think of "x" as a vertical value, since it moves a point vertically.

So just by looking at the graph, you can easily determine that the eclipse has a horizontal major axis. This can be further proven, since the distance from the origin on the right side is 28, and the distance from the the top to the origin is only 20.

So you could set up an equation to solve for a, since 2a = length of major axis, but since we're given the two points, the "a" value is really just the length from the origin to the right/left side, and combining these together you get the value of 2a/major axis, but you don't have to do that. So by looking at the graph you'll see the distance from the origin to the right side is 28. This means "a=28"

You can do the same thing here for the "b" value, and since the top is 20 units away from the origin, "b = 20"

So now let's set up the equation:
$\frac{x^2}{28^2} + \frac{y^2}{20^2}=1$