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3 years ago

PLEASE HELP JESUS I DONT UNDERSTAND

Mathematics

2 answers:

Alex787 [66]3 years ago

8 0

Answer:

22 units

Step-by-step explanation:

The formula for the area of a trapezoid is A = $\frac{a+b}{2} h$ where a and b are the <u>bases</u> and h is the <u>height</u> of the trapezoid.

In this case, the numbers that will be replacing a and b will be 4 and 7, making the equation look like this: A = $\frac{4+7}{2}h$ .

Now, you have to determine the height of the trapezoid, which in this case is 4 units. The equation will now look like this: A = $\frac{4+7}{2}4$ .

You can solve from here like so:

A = $\frac{11}{2}4$

A = 5.5(4)

A = 22

sorry that took long :3))

I got the measurements like 4, 7, and the other 4 from rotating the shape to have the longer side on the bottom.

densk [106]3 years ago

7 0

Answer:

i just need points my man buts its A

Step-by-step explanation:

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A man drove 210 miles in 3.5 hours. If the posted speed limit was 55 mph (miles per hour) the entire way, approximately how many

Alona [7]

Answer:

5mph over the speed limit

Step-by-step explanation:

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5 0

3 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$