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3 years ago

14

Harry and Helen are married, filing jointly. Their combined taxable income is $65,922. Every week, a total of $187 is withheld f

rom their pay. Based on the table below, what can Harry and Helen expect when their taxes are due?

2 answers:

Xelga [282]3 years ago

3 0

They will have 66,039

Sholpan [36]3 years ago

3 0

Answer:

B

Step-by-step explanation:

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PLeAsE do this!! In five minutes it's due.

Orlov [11]

Answer:

It's (7x+2)(3x−2)

Step-by-step explanation:

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3 years ago

Read 2 more answers

The CEO of a large corporation asks his Human Resource (HR) director to study absenteeism among its executive-level managers at

Fynjy0 [20]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given:

n = 30 is the sample size.

The mean $\bar X$ = 7.3 days.

The standard deviation = 6.2 days.

df = n-1

$= 30-1 \\ =29$

The importance level is $\alpha$ = 0.10

The table value is calculated with a function excel 2010:

$= tinv (\ probility, \ freedom \ level) \\= tinv (0.10,29) \\ =1.699127\\ = t_{al(2x-1)}= 1.699127$

The method for calculating the trust interval of 90 percent for the true population means is:

Formula:

$\bar X - t_{al 2,x-1} \frac{S}{\sqrt{n}} \leq \mu \leq \bar X+ t_{al 2,x-1} \frac{S}{\sqrt{n}}$

$=\bar X - t_{0.5, 29} \frac{6.2}{\sqrt{30}} \leq \mu \leq \bar X+ t_{0.5, 29} \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 \frac{6.2}{\sqrt{30}}\leq \mu \leq7.3 +1.699127 \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 (1.13196)\leq \mu \leq7.3 +1.699127 (1.13196) \\\\=5.37 \leq \mu \leq 9.22 \\$

It can rest assured that the true people needs that middle managers are unavailable from 5,37 to 9,23 during the years.

7 0

3 years ago

Which of the following situations result in an answer of 2/3? Select three that apply.

Tema [17]

B: is the best answer because there splitting 2 apples among 3 people and that means there’s not enough for all, so they all receive 2/3 of an apple to all get shared with equally. Hopefully this helps!

6 0

3 years ago

If the terminal side of an angle (θ) goes through the point (4 , -3) what is (θ)?

almond37 [142]

Answer:

The family of directions of the given vector is represented by $\theta = 323.130^{\circ} \pm 360\cdot i$ , $\forall \,i\in \mathbb{N}_{O}$ .

Step-by-step explanation:

According to the given information, vector stands in the 4th Quadrant ( $x > 0$ , $y < 0$ ) and direction of the vector ( $\theta$ ) in sexagesimal degrees, is determined by following definition:

$\theta = 360^{\circ} - \tan^{-1} \left(\frac{|y|}{|x|} \right)\pm 360\cdot i$ , $\forall \,i\in \mathbb{N}_{O}$

Please notice that angle represents a function with a periodicity of 360°.

If we know that $x = 4$ and $y = -3$ , then the direction of the vector is:

$\theta = 360^{\circ}-\tan^{-1}\left(\frac{|-3|}{|4|} \right)\pm 360\cdot i$

$\theta = 323.130^{\circ} \pm 360\cdot i$

The family of directions of the given vector is represented by $\theta = 323.130^{\circ} \pm 360\cdot i$ , $\forall \,i\in \mathbb{N}_{O}$ .

3 0

3 years ago

I need help with 3 please!

Ksivusya [100]

Answer:

Step-by-step explanation:

PQ=24

PS=19

PR=42

TQ=10

QR=19

SR=24

PT=21

SQ=20

m∠QRS=180-m∠PQR=180-106=74°

m∠PQS=m∠QSR=49°

m∠RPS=m∠PRQ=m∠QRS-m∠PRS=74-35=39°

m∠PSQ=m∠RQS=m∠PQR-m∠PQS=106-49=57°

m∠PQR=106°

m∠ QSR=49°

M∠PRS=35°

8 0

4 years ago