Answer:
t =1.453 decades from 1980 i.e in year 1994.5
Step-by-step explanation:
Given:
- Population @ year 1980 P = 678.97 thousands.
- Population @ year 2000 P = 776.73 thousands.
- The rate of increase is linear - constant rate.
Find:
As the population of San Francisco was revitalizing, for what value of the independent variable t did it reach 750 thousand ?
Solution:
- Develop an expression of population P as a function of time t in decades elapsed from year 1980 on-wards
- The linear expression can take a form of :
P(t) = m*t + C
- Where, m is the rate of increase.
C is the initial population.
- Formulate m:
m = (776.73 - 678.97) / 2 = 48.88
- Formulate C:
C = P (@ 1980) = 678.97
- Evaluate P(t) = 750:
P(t) = 48.8*t + 678.97
750 = 48.8*t + 678.97
t = 71.03/48.8
t =1.453 decades
The loudness in decibels is
L = log₁₀(I/I₀)
where
I = sound intensity, W/m^2
I₀ = reference intensity, = 10^(-12) W/m^2
Raja's power level is 10^(-7) W, therefore the decibel value is
L = 10 log₁₀(10^(-7)/10^(-12))
= 10log₁₀10^5
= 10*5
= 50 dB
Answer: 50 dB
Total number of cards in the deck = 52
Total number of queens = 4
P(Queen) = 4/52 = 1/13
Answer: 1/13
y=∣x−1∣={
1−x
x−1
x<1
x≥1
}
Similarly y=3−∣x∣={
3+x
3−x
x<0
x≥0
}
The required region is a rectangle with length 2
2
and breadth
2
.
Hence, the area is 4. Hence, all the options are correct
Let the number of each coin be n.
The total sum of these coins is $4.40. So we can write:
n Nickles + n Dimes + n Quarters = 4.40
0.05n + 0.10n + 0.25n = 4.40
0.40n = 4.40
n = 11
So this means, there are 11 coins of each type.
