All categories

2 years ago

Katie left at 4:00 p.m. to bike to school. It took her 30 minutes to bike there.

Mathematics

2 answers:

Rainbow [258]2 years ago

6 0

Answer:

Katie got to school at 4:30

Step-by-step explanation:

Drupady [299]2 years ago

6 0

Answer:

4:30 pm

Step-by-step explanation:

She left at 4:00. In the question it says that it took 30 minutes to get there, and 30minutes after 4:00 pm is 4:30pm.

You might be interested in

The Wilson family is going to an amusement park for the day. The park charges $15 per vehicle for parking. The cost of each admi

Vladimir79 [104]

Answer:

Step-by-step explanation:

5 0

2 years ago

Could somebody please help me find the answers for 'x' for these pictures?

lesya692 [45]

Answer:

Pic 1: $x=31$

Pic 2: $x=20$

Step-by-step explanation:

Picture 1:

$2x+x-3=90\\3x-3=90\\3x=93\\x=31$

First, add the 2x and x together for 3x

Then add 3 to both sides of the equation

Finally, divide each side by 3.

Picture 2:

$7x+x+20=180\\8x+20=180\\8x=160\\x=20$

First, add 7x and x together for 8x

Then, minus 20 from both sides of the equation

Finally, divide each side by 8.

8 0

2 years ago

Read 2 more answers

Name three pairs of numbers that have 5 as their gfc (Greatest Common factor). Use each number once in your answer. I really nee

katen-ka-za [31]

20,25 and 35,50 and 10,15. Each pair would have a GCF of 5.

4 0

2 years ago

Read 2 more answers

How do you this question (pre-cal)

Novay_Z [31]

The goal to proving identities is to transform one side into the other. We can only pick one side to transform while the other side stays the same the entire time. The general rule of thumb is to transform the more complicated side (though there may be exceptions to this guideline).

So I'll take the left hand side and try to turn it into $\csc^2( B )$

One way we can do that is through the following steps:

$\frac{\tan(B) + \cot(B)}{\tan(B)} = \csc^2(B)\\\\\frac{\tan(B)}{\tan(B)} + \frac{\cot(B)}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\frac{1}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\cot(B) = \csc^2(B)\\\\1 + \cot^2(B) = \csc^2(B)\\\\1 + \frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)}{\sin^2(B)}+\frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)+cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{1}{\sin^2(B)} = \csc^2(B)\\\\\csc^2(B)=\csc^2(B) \ \ {\Large \checkmark}\\\\$

Since we've shown that the left hand side transforms into the right hand side, this verifies the equation is an identity.

4 0

3 years ago

Can two different integers have the same absolute value?

kotegsom [21]

8 and -8 both of their absolute values are 8

6 0

3 years ago

Read 2 more answers