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3 years ago

A fair spinner has 11 equal sections: 4 red, 4 blue and 3 green.

Mathematics

1 answer:

djyliett [7]3 years ago

6 0

The probability of getting the same colour twice is approximately 34%.

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The equation that represents the canned goods order is 24x + 64y = 384, where x = number of minutes spent producing fruit cans,

Lubov Fominskaja [6]

So wee need to find x

4 0

3 years ago

Read 2 more answers

In a recent survey, 40 percent indicated chocolate was their favorite flavor of ice cream. Suppose we select a sample of twelve

worty [1.4K]

Answer:

4 people name chocolate

Step-by-step explanation:

Let's first understand the given information.

The survey shows that 40 percent of a finite number of people name chocolate as their favorite flavor of ice cream. Because the survey is reporting a percentage, then 40% means that from 100 people 40 people name chocolate, while the others name a different type of flavor.

Dividing the total of people (100) by the ones who name chocolate (40) then we have:

100/40 = 2.5

Through the above equation we are actually expressing the following:

Total people = 2.5 * (people who name chocolate flavor)

Using this equation if we have now 12 people:

12 = 2.5 * (people who name chocolate flavor)

12/2.5 = (people who name chocolate flavor)

4.8 = people who chose chocolate flavor

Because we can't have 0.8 of a person, then if we have a sample of 12 people, we will expect that 4 of them name chocolate.

5 0

3 years ago

Please help :(<br><br>thank you!

harina [27]

Answer:

pls stop deleting my answers brainly thx. also its b! ^-^

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Assume that a procedure yields a binomial distribution with a trial repeated n = 5 times. Use some form of technology to find th

Digiron [165]

Answer:

$P(X = 0) = 0.0263$

$P(X = 1) = 0.1407$

$P(X = 2) = 0.3012$

$P(X = 3) = 0.3224$

$P(X = 4) = 0.1725$

$P(X = 5) = 0.0369$

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 5, p = 0.517$

Distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263$

$P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407$

$P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012$

$P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224$

$P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725$

$P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369$

6 0

3 years ago

How do i do 3 part a ?

WINSTONCH [101]

In general the binomial expansion is

$(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0$

So in our case, because we want ascending powers of x we'll write,

$(-3x + 1)^{11} = {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9 + {11 \choose 3 } (-3x)^3 1^8 + ...$

We need to calculate the binomial coefficients:

${11 \choose 0} = 1$

${11 \choose 1} = 11$

${11 \choose 2} = \dfrac{11 \times 10}{2} = 55$

${11 \choose 3} = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165$

$(-3x+1)^{11} = 1 (-3x)^0 1^{11} + 11(-3x)^{1} 1^{10} + 55 (-3x)^2 1^{9} + 165 (-3x)^3 1^8 + ...$

$(1-3x)^{11} = 1 -33 x + 495 3x^2 - 4455 x^3+ ...$

6 0

3 years ago