Question

Divide 81 -x^2 y^2 by (9-xy) (3 + xy)​

Answer 1

Answer:

When we divide 81 -x²y² by (9-xy) (3 + xy)​, we determine the expression is:

$\frac{81-x^2y^2}{\left(9-xy\right)\left(3+xy\right)}=\frac{9+xy}{3+xy}$

Step-by-step explanation:

Let us divide 81 -x²y² by (9-xy) (3 + xy)​

so

Given the expression

$\frac{81-x^2y^2}{\left(9-xy\right)\left(3+xy\right)}$

Factor -x²y² + 81 = (9+xy) (9-xy)

$\frac{81-x^2y^2}{\left(9-xy\right)\left(3+xy\right)}=\frac{\left(9+xy\right)\left(9-xy\right)}{\left(9-xy\right)\left(3+xy\right)}$

Cancel the common term: 9-xy

                    $=\frac{9+xy}{3+xy}$

Therefore, when we divide 81 -x²y² by (9-xy) (3 + xy)​, we determine the expression is:

$\frac{81-x^2y^2}{\left(9-xy\right)\left(3+xy\right)}=\frac{9+xy}{3+xy}$