Answer:
dy/dt = - (1/5) ft/s = - 0.2 ft/s
Step-by-step explanation:
Given
L = 5 ft
Qin = 25 ft³/s
Qout = 30 ft³/s
h = 10 ft
dy/dt = ?
We can apply the relation
ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s
⇒ ΔQ = - 5 ft³/s
Then we use the formula
Q = v*A
where Q = ΔQ, A = L² is the area of square base and v = dy/dt is the rate of change in the depth of the solution in the tank
⇒ ΔQ = (dy/dt)*L²
⇒ dy/dt = ΔQ/L²
⇒ dy/dt = (- 5 ft³/s)/(5 ft)²
⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s
Answer:
S.I= 640
Step-by-step explanation:
I=prt
where p= $8,000
and r= 4%
and t= 2 years
$8,000×4%×2
8,000×4/100×2
80×4×2
=640
Therefore The S.I = 640.
Answer:
The Answer is A.) -4
Step-by-step explanation:
The answer is linear and increasing. look at it.... it goes up.
Fifteen thousand six-hundred and thirty-eight
