Question

A cylinder with a radius of 6cm and height of 15 cm has a cylindrical cut out of the

Answer 1

Answer:

$V = 518cm^3$

Step-by-step explanation:

Given

$h = 15cm$

$R = 6cm$

$r =5cm$

Required

The volume of the remaining cylinder

Before the cut-out, the cylinder has a volume (V) of:

$V = \pi R^2h$

After the cut-out, the cylinder has a volume of:

$V = \pi [R^2 -r^2]h$

So, we have:

$V = 3.14* [6^2 -5^2]*15$

$V = 3.14* [36 -25]*15$

$V = 3.14* 11*15$

$V = 518cm^3$