The amount of substance left of a radioactive element of half life,

after a time, t, is given by:

Given that <span>potassium-40 has a half life of approximately 1.25 billion
years.
The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:

Therefore, </span><span>the maximum age of a fossil that we could date using 40k is
12.5 billion years.</span>
Answer:
5/12
Step-by-step explanation:
The answer is 2 feet it is equal to two feet
Answer:
92.75 miles per 7 days
Step-by-step explanation:
13.25 mi/day times 7 days works out to 92.75 miles per 7 days.