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dimaraw [331]
3 years ago
10

Given T5 = 96 and T8 = 768 of a geometric progression. Find the first term,a and the common ratio,r.

Mathematics
2 answers:
Elanso [62]3 years ago
6 0

Step-by-step explanation:

First Term of the Geometric Sequence: 6

a = 6

Common Ratio: 2

nth Term of the Sequence Formula: an=6⋅2^n−1

vaieri [72.5K]3 years ago
3 0

Answer:

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PLEASE ANSWER!!!
marin [14]

Step-by-step explanation:

(10-0) ÷ (27-0) = x ÷ y

10 ÷ 27 = x ÷ y

27x = 10y

2,7x = y

The third one

8 0
3 years ago
Read 2 more answers
If you are solving the equation by factoring, which of the following equations would you use the zero product property on?
Artist 52 [7]

Answer:

(x + 5)(x + 10) = 0

Step-by-step explanation:

When you solve for the equation: \frac{1}{x-4}-\frac{14}{x+2}+1=0, you get that the answer is x=10,\:x=5.

<em>Hope this helped!!</em>

8 0
3 years ago
I need help!! This is getting a little harder than I expected
MAXImum [283]

Length of the side = 9 cm

Diagonal = 9\sqrt{2} cm

Solution:

Area of the square = 81 square centimeters

In square all sides are equal.

Area of the square = side × side

Side × side = 81

Side² = 9²    (∵81 = 9²)

Taking square root on both sides, we get

Side = 9 cm

Length of the side = 9 cm

To find the length of the diagonal:

In square all the angles are right angle.

Diagonal splits the square into two right angle triangle.

Using Pythagoras theorem,

<em>In right triangle, square of the hypotenuse is equal to the sum of the square of the other two sides.</em>

Here, diagonal is the hypotenuse.

\text{Diagonal}^2=9^2+9^2

\text{Diagonal}^2=81+81

\text{Diagonal}^2=2\times 81

Taking square root on both side,

Diagonal = 9\sqrt{2} cm

6 0
3 years ago
What is -(1)<br>Please help me.
KatRina [158]
It Is Just -1.
The Parenthesis Are All Simplified, And The Subtraction Sign Changes It To Negative. So, 1 Changed To Negative Is -1. <span />
8 0
3 years ago
Which statement about the net is true?
Ivanshal [37]

Answer:

A

Step-by-step explanation:

The net can be folded to form a pyramid

4 0
2 years ago
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