Given
Expenditures at Manager's Store; expenditures at Competitor's Store.
Find
a) average spent at each store
b) which store is better represented by the mean value
c) an explanation for the answer in ≥ 2 sentences
Solution
a) The sum of expenditures divided by the number of expenditures (15) is ...
... average for Manager's Store: $37.60
... average for Competitor's Store: $48.53
b) The expenditures at Manager's Store are well-represented by the mean (average).
c) The range of expenditures at Competitor's Store is significantly higher than at Manager's store, so a single number such as mean or median does not represent the data well. The expenditures at Manager's store are more compactly grouped around the mean and median, which are closer together, so the mean is a good representation of Manager's Store expenditures overall.
Answer:
a = 23.588
Step-by-step explanation:
a^2 = 17 1/3^2 + 16^2
a^2 = 300.4 + 256
a^2 = 556.4
a = 23.588 (I rounded to thousandths but you can round to whatever)
Answer:8600
Step-by-step explanation:
477
Alright, let's factor this to get the answer.
3k^2-10k+7
To find the factors, we want to think "What will add up to -10, and multiply to (+)7?"
Because the leading coefficient is 3, we know that we can take one factor of 7 and multiply it by 3.
Thus, this factors to
(3k-7)(k-1)
(if you FOIL it it should come out to be the original equation)
From this, set both of those [(3k-7) and (k-1)] equal to zero and solve
3k-7=0
3k=7
/3
k=7/3
or
k=1
