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Sergeeva-Olga [200]
4 years ago
7

For a snack, Sameer ate a plum with 32 calories and several strawberries with 4 calories each. If the total of calories in Samee

r’s snack was 56, how many strawberries did he eat?
Mathematics
1 answer:
irinina [24]4 years ago
6 0

Answer: 6

Step-by-step explanation:

So to find the answer, we would use the equation 32+4x=56 where as x represents the amount of strawberries Sameer ate. Now to solve for x

56-32=4x

24=4x

now divide 4 from bboth sides of the equation getting:

x=6

so Sameer ate 6 strawberries

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A passbook saving account has a rate of 6%. find the effective annual yield, rounded to the nearest tenth of a percent, if the i
irinina [24]

Answer:

a,b,c,d,e,f) The effective annual yield is 1.1P-P = 0.1P = 10%P.

Step-by-step explanation:

This is a compound interest problem

Compound interest formula:

The compound interest formula is given by:

A = P(1 + \frac{r}{n})^{nt}

A: Amount of money(Balance)

P: Principal(Initial deposit)

r: interest rate(as a decimal value)

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t: time the money is invested or borrowed for.

a)

r = 0.06

n: 2(semianually means that the interest is compounded twice a year).

t = 1.

A = P(1 + \frac{0.06}{2})^{2*1}

A = 1.1P

The acount started the year with P, and it ended with 1.1P, so the effective annual yield is 1.1P-P = 0.1P = 10%P.

b)

Now we have n = 3, since if the interest is compounded quarterly, is is compounded three times a year(a year has 3 quarters). So:

A = P(1 + \frac{0.06}{3})^{3*1}

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The effective annual yield is 1.1P-P = 0.1P = 10%P.

c) Now we have n = 12, since the interest is compounded monthly, and there are 12 months a year. So:

A = P(1 + \frac{0.06}{12})^{12*1}

A = 1.1P

The effective annual yield is 1.1P-P = 0.1P = 10%P.

d) Since the interest is compounded daily, and we assume 360 days in a year, n = 360. So:

A = P(1 + \frac{0.06}{360})^{360*1}

A = 1.1P

The effective annual yield is 1.1P-P = 0.1P = 10%P.

e) The interest is compounded 1000 times a year, so n = 1000

A = P(1 + \frac{0.06}{1000})^{1000*1}

A = 1.1P

The effective annual yield is 1.1P-P = 0.1P = 10%P.

f) The interest is compounded 100000 times a year, so n = 100000

A = P(1 + \frac{0.06}{100000})^{100000*1}

A = 1.1P

The effective annual yield is 1.1P-P = 0.1P = 10%P.

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