P(x) 3x^2 + 5x^2 + 4x-7 andq (x)=6x^3+ 2x^2-9x-5Find P(x)+ q (x) and P[x]-q(x)
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Well, what I would do [not sure if it's the correct way], is use the white area as a sector of a circle. The top right of the box is the center of the circle, so the radius is 6.
Then, by the white portion being one quarter of the circle (90° out of 360°), I could calculate the that pink shaded region = the total square (6×6) minus the white sector.
So area (A) of white sector (s): A(s) = 1/4×pi×r^2
36 - 28.27 = 7.73
Then, by the white portion being one quarter of the circle (90° out of 360°), I could calculate the that pink shaded region = the total square (6×6) minus the white sector.
So area (A) of white sector (s): A(s) = 1/4×pi×r^2
36 - 28.27 = 7.73
