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vfiekz [6]
3 years ago
5

P(x) 3x^2 + 5x^2 + 4x-7 andq (x)=6x^3+ 2x^2-9x-5Find P(x)+ q (x) and P[x]-q(x)​

Mathematics
1 answer:
nikdorinn [45]3 years ago
6 0

Answer:

P(x) + q(x)

= (3x² + 5x² + 4x - 7) + (6x³ + 2x² - 9x - 5)

= 3x² + 5x² + 4x - 7 + 6x³ + 2x² - 9x - 5

= 6x³ + 10x² - 5x - 12

P(x) - q(x)

= (3x² + 5x² + 4x - 7) - (6x³ + 2x² - 9x - 5)

= 3x² + 5x² + 4x - 7 - 6x³ - 2x² + 9x + 5

= -6x³ + 6x² + 13x - 2

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Why is 1 + (−5) equal to −4?
ruslelena [56]

Answer:

because its 5 units to the left on a horizontal number line

8 0
3 years ago
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a florist makes 24 bouquets she uses 16 flowers for each bouquet altogether how many flowers does she use?
NNADVOKAT [17]

Answer:

384

Step-by-step explanation:

24 bouquets * 16 flowers = 384 flowers


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Thank you for using Brainly!

7 0
3 years ago
Given f (x)=-3x+4 what is f (-4)<br> a.-40<br> b.-22<br> c.-1<br> d.40
FinnZ [79.3K]
F(x)=-3(x)+4
Therefore this implies that we must put the -4 where we see an X on the equation
F(-4)=-3(-4)+4
=16
6 0
3 years ago
What is a shape that has <br> 3 faces<br> 2 edges<br> No vertices ??<br> Please help!
mart [117]
Hello!

A cylinder has 3 faces 2 edges and 0 vertices

The answer is cylinder

Hope this helps!
6 0
3 years ago
Radioactive Decay Beginning with 16 grams of a radioactive element whose half -life is 30 years ,the mass y(in grams) remaining
Flura [38]

Answer:

the equation should be corrected to fit the data of the problem.  With the corrected equation a mass of 0.5 grams remains after 150 years

Step-by-step explanation:

for the mass y( in grams)

y=23* (1/2)^(t/45), t ≥ 0.

the initial mass is at t=0 , then

y= 23 grams  → should be 16 grams

half-life from the equation = 45 years → should be 30 years

the correct equation should be

y=16*(1/2)^(t/30), t ≥ 0

then after 150 years  → t= 150

y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams

then a mass of 0.5 grams remains after 150 years

5 0
3 years ago
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