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Zigmanuir [339]
3 years ago
15

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

ct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Complete the following proof.

Given: RS tangent to circle A and circle B
at points R and S



Prove: AR parallel to BS

Mathematics
1 answer:
Allisa [31]3 years ago
4 0

Step-by-step explanation:

Statements

1.RS tangent to circle A and circle B at point R and point S

2.AR is perpendicular to RS, BS is perpendicular to RS

3.AR is parallel to BS

Reasons

1.Given

2.Radius are perpendicular to tangent

3. 2 lines perpendicular to the same line are parallel to each other

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A line that goes through the x axis or y axis
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3 years ago
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For every 6kg a child's weight, pediatricians prescribe 17mg of acetaminophen. If Lexie weighs 48 kg, how many milligrams of the
Inessa05 [86]
The answer will be 136mg
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3 years ago
What is 8.038×108 in standard form?
skad [1K]
Okay. I think what you mean by this is 8.038 * 10^8. 10^8 = 100,000,000. When you multiply that by 8.038, you get 803,800,000. The answer is D.
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3 years ago
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Let X be the temperature in at which a certain chemical reaction takes place, and let Y be the temperature in (so Y = 1.8X + 32)
Black_prince [1.1K]

Answer:

See explanation

Step-by-step explanation:

Solution:-

The random variable, Y be the temperature of chemical reaction in degree fahrenheit be a linear expression of a random variable X : The  temperature in at which a certain chemical reaction takes place.

                             Y = 1.8*X + 32

- The median of the random variate "X" is given to be equal to "η". We can mathematically express it as:

                             P ( X ≤ η ) = 0.5

- Then the median of "Y" distribution can be expressed with the help of the relation given:

                             P ( Y ≤ 1.8*η + 32 )

- The left hand side of the inequality can be replaced by the linear relation:

                             P ( 1.8*X + 32 ≤ 1.8*η + 32 )

                             P ( 1.8*X ≤ 1.8*η )   ..... Cancel "1.8" on both sides.

                            P ( X ≤ η ) = 0.5 ...... Proven

Hence,

- Through conjecture we proved that: (1.8*η + 32) has to be the median of distribution "Y".

b)

- Recall that the definition of proportion (p) of distribution that lie within the 90th percentile. It can be mathematically expressed as the probability of random variate "X" at 90th percentile :

                             P ( X ≤ p_.9 ) = 0.9 ..... 90th percentile

- Now use the conjecture given as a linear expression random variate "Y",

          P ( Y ≤ 1.8*p_0.9 + 32 ) = P ( 1.8*X + 32 ≤ 1.8*p_0.9 + 32 )

                                                 = P ( 1.8*X ≤ 1.8*p_0.9 )

                                                 = P ( X  ≤ p_0.9 )

                                                 = 0.9

- So from conjecture we saw that the 90th percentile of "X" distribution is also the 90th percentile of "Y" distribution.

c)

- The more general relation between two random variate "Y" and "X" is given:

                            Y = aX + b

Where, a : is either a positive or negative constant.

- Denote, (np) as the 100th percentile of the X distribution, so the corresponding 100th percentile of the Y distribution would be : (a*np + b).

- When a is positive,

                   P ( Y ≤ a*p_% + b ) = P ( a*X + b ≤ a*p_% + b )

                                                 = P ( a*X ≤ a*p_% )

                                                 = P ( X  ≤ p_% )

                                                 = np_%        

- When a is negative,

                   P ( Y ≤ a*p_% + b ) = P ( a*X + b ≤ a*p_% + b )

                                                 = P ( a*X ≤ a*p_% )

                                                 = P ( X  ≥ p_% )

                                                 = 1 - np_%        

                                                           

4 0
3 years ago
PLEASE HELP!!! Does anyone know the answer to this?!? (Y^3z^4)^(-3/4)
Svetach [21]

Answer:

y^ ⁻⁹/⁴ * z^⁽⁻³⁾

Step-by-step explanation:

(Y^3 z^4)^(-3/4)   = (y^3)^(-3/4) * (z^4)^(-3/4)

         =  y^3* ⁽⁻³/⁴⁾   * z^4 *⁽⁻³/⁴⁾

           =y^ ⁻⁹/⁴ * z^⁽⁻³⁾

5 0
3 years ago
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