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pogonyaev
3 years ago
8

At Midland Elementary, there are 22 students in each of seven fourth- grade classes. How many students are in fourth-grade at Mi

dland?pls help me asap​
Mathematics
1 answer:
qwelly [4]3 years ago
7 0
154 students are in fourth grade at Midland
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5 raised by 2- 5 (68-60)= <br> (with explanation plz)
Arlecino [84]

Step-by-step explanation:

2-5(68-60)=2-5×8=2-40=38

6 0
3 years ago
P=2L +2W;P=32,W=7<br><br> 25<br> 16<br> 12.5<br> 9
Marianna [84]

Answer:

L = 9

Step-by-step explanation:

Assuming you are trying to find L

P = 2L + 2W

P = 32

32 = 2L + 2W

W = 7

32 = 2L + (2 × 7)

32 = 2L + 14

2L = 32 - 14

2L = 18

L = 9

5 0
3 years ago
Calculate S58 for the arithmetic sequence {an}= {5/6n+1/3} If you could show me the steps that would be great. I keep following
Amanda [17]

Answer is 8671/6 which is the third choice

===================================

Work Shown:

Find the first term of the sequence by plugging in n = 1

a_n = (5/6)*n + 1/3

a_1 = (5/6)*1 + 1/3    replace n with 1

a_1 = 5/6 + 1/3

a_1 = 5/6 + 2/6

a_1 = 7/6

Repeat for n = 58 to get the 58th term

a_n = (5/6)*n + 1/3

a_58 = (5/6)*58 + 1/3    replace n with 58

a_58 = (5/6)*(58/1) + 1/3

a_58 = (5*58)/(6*1) + 1/3

a_58 = 290/6 + 1/3

a_58 = 145/3 + 1/3

a_58 = 146/3

Now we can use the s_n formula below with n = 58

s_n = (n/2)*(a_1 + a_n)

s_58 = (58/2)*(a_1 + a_58)    replace n with 58

s_58 = (58/2)*(7/6 + a_58)   replace a_1 with 7/6

s_58 = (58/2)*(7/6 + 146/3)   replace a_58 with 146/3

s_58 = (58/2)*(7/6 + 292/6)

s_58 = (58/2)*(299/6)

s_58 = (58*299)/(2*6)

s_58 = 17342/12

s_58 = 8671/6


5 0
3 years ago
Above is a table with missing terms. Come up with a possible common difference that makes sense and list the missing terms.
Rina8888 [55]

Answer:

common ratio:2 2. 18  3.36  4.72 equation: 4.5(2^x)

Step-by-step explanation:

144=2*2*2*2*3*3    9=3*3

the common ratio would be 2

2. 9*2=18

3. 18*2=36

4. 36*2=72

(check) 72*2=144

0. 9/2=4.5

equation: 4.5(2^x)

7 0
3 years ago
A segment bisector makes two segments that have equal length?
dedylja [7]
True by definition <span>In general 'to bisect' something means to cut it into two equal parts. The 'bisector' is the thing doing the cutting </span>
6 0
4 years ago
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