3y = -2x + 2
y = x + 4 (Substitute the y)
3(x + 4) = -2x + 2 (Distribute)
3x + 12 = -2x + 2 (Add 3 to both sides)
+3x +3x
------------------------------------------
12 = 1x + 2 (Subtract 2 from both sides)
-2 - 2
------------------------
10 = 1x (Divide by 1 on both sides)
10/1 = 1x/1
x = 10
This is your x-coordinate
well and 300% increase means you multiply by 3 and then add the original number
in this case 300% of 25 is 75 and its an increase so 25+75=100
the answer is 100
Answer:
2, 7, 114
Step-by-step explanation:
(3 + 0.5x)(38 - 4x)
114 + 19x - 12x - 2x²
-2x² + 7x + 114
Answer:
x = 11
Step-by-step explanation:
Answer:
95% of monthly food expenditures are between $110 and $190.
Step-by-step explanation:
Given : The monthly amounts spent for food by families of four receiving food stamps approximates a symmetrical, normal distribution. The sample mean is $150 and the standard deviation is $20.
To find : Using the Empirical rule, about 95% of the monthly food expenditures are between which of the following two amounts?
Solution :
At 95% of the data is between two standard deviation to left and right of the mean is given by,
To the left side, ![\bar{x}-2\sigma](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D-2%5Csigma)
To the right side, ![\bar{x}+2\sigma](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%2B2%5Csigma)
We have given,
The sample mean ![\bar{x}=\$150](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D%5C%24150)
The standard deviation ![\sigma=\$20](https://tex.z-dn.net/?f=%5Csigma%3D%5C%2420)
Substitute in the formula,
![\bar{x}-2\sigma](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D-2%5Csigma)
![=150-2(20)](https://tex.z-dn.net/?f=%3D150-2%2820%29)
![=150-40](https://tex.z-dn.net/?f=%3D150-40)
![=110](https://tex.z-dn.net/?f=%3D110)
![\bar{x}+2\sigma](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%2B2%5Csigma)
![=150+2(20)](https://tex.z-dn.net/?f=%3D150%2B2%2820%29)
![=150+40](https://tex.z-dn.net/?f=%3D150%2B40)
![=190](https://tex.z-dn.net/?f=%3D190)
Therefore, 95% of monthly food expenditures are between $110 and $190.