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gogolik [260]
3 years ago
13

HELP HURRY NEED WORK SHOWN 20 POINTS

Mathematics
1 answer:
Vlada [557]3 years ago
7 0
18 and your home schooled I go to public school
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Domain and rang of these
RideAnS [48]

Answer:

Domain: {-3, -1, 1}

Range: {-1, 2, 4, 5}

Step-by-step explanation:

The domain is all the x-values, and the range is all the y-values. When listing values, repeated values are only written down once.

6 0
2 years ago
Jason is training to run in a marathon. His goal for this week is to run a minimum of 35 miles.
Illusion [34]

Answer:

5 miles a day.

Step-by-step explanation:

if there's 35 and he has done 15 he will have to do 5 miles each day (4 days) which will be 20, when added equivalent to 35.

3 0
2 years ago
10. Suppose y varies directly as x, and y = 9 when x = 3/2. Find y when x = 1
pogonyaev

Answer:

y = 6

Step-by-step explanation:

We need to interpret the question

y varies directly as x

y varies x

To equate it, we need to add a constant K

y = K/x

Using the information we are provided with

y = 9

x = 3/2

insert into

y = Kx

9 = K * 3/2

9 = 3K/ 2

3K = 9 *2

3k = 18

To get K, divide through by 3

3K/3 = 18/3

K = 6

Since we've gotten our K = 6

y = Kx

Using the new information

y = ?

x = 1

K = 6

y = 6* 1

y = 6

The new y = 6 , x =1

6 0
3 years ago
Where does the line through (1, 0, 1) and (4, −3, 3) intersect the plane x + y + z = 6?
Irina-Kira [14]

Parametrically for real t the line is


(x,y,z) = (1-t)(1,0,1) + t(4,-3,3)


(x,y,z) = (1,0,1) + t(4-1,-3-0,3-1)


(x,y,z) = (1,0,1) + t(3,-3,2)


That's three equations; we substitute into


x+y+z=6


(1+3t)+(0-3t) + ( 1+2t)=6


2t=4


t=2


(x,y,z) = (1,0,1) + 2(3,-3,2) = (7,-6,5)


The intersection is a single point (7,-6,5).



7 0
3 years ago
A consumer organization that evaluates new motorcycles customarily reports the number of major defects in each motorcycle examin
koban [17]

Answer:

a) F(2)=0.30

b)P(X>3)=0.7

c)P(2≤X≤5)=0.67

d)P(2<X<5)=0.71

Step-by-step explanation:

a) F(2)=P(X≤2)=0.30

F(2) is given in the probability distribution

b) P(X>3)=1-P(X≤2)=1-F(2)=1-0.3=0.7

P(X>3)=0.7

c)P(2≤X≤5)=?

As we know that P(a≤X≤b)=F(b)-F(a)=P(X≤b)-P(X≤a)

So,

P(2≤X≤5)=P(X≤5)-P(X≤2)=F(5)-F(2)=0.97-0.3=0.67

P(2≤X≤5)=0.67

d)P(2<X<5)=P(1≤X≤4)=P(X≤4)-P(X≤1)=F(4)-F(1)=0.91-0.2=0.71.

P(2<X<5)=0.71

5 0
3 years ago
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