Answer:
at 2/3 seconds
Step-by-step explanation:
S1(t) = t³ + 2
Average speed, dS1/dt = 3t²
S2(t) = t²
Average speed, dS2/dt = 2t
The distance between the objects is
dS1/dt - dS2/dt
= 3t² - 2t
The time the distance between the two object is at minimum is when the distance is 0
That is, when
3t² - 2t = 0
t(3t - 2) = 0
t = 0 or 3t - 2 = 0
t = 0 or t = 2/3
Answer:
let me just say this
Step-by-step explanation:
you're luck not mine so sorry if this didnt help
Answer:
x=-2 y=3
Step-by-step explanation:
The substitution is basically given to you. Exchange x from the second equation with y-5
Once that is done and you combine the parentheses you get:
2y-10+y=-1
Add 10 on both sides of the equal sign
You get:
3y=9
Divide both sides by 3
You get:
y=3
To check your work you can substitute y in the second equation with 3 and solve it that way to get x=-2 (x equals negative two)
Answer:
I want to say its 50%
Step-by-step explanation:
Answer:
BBAB
Step-by-step explanation:
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