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3 years ago

A woodworker wants to cut a board that is 22.8718 feet long into 7 equal-length pieces

Mathematics

1 answer:

Andreyy893 years ago

4 0

Answer:

3.2674

Step-by-step explanation:

divide 22.8718 by 7 to get your answer

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Given logbM=3.2 logbN=-1.5 and logbP=2.4 find the value of logb(m^2N/p)

artcher [175]

The formulas:
$\log_a (xy)=\log_a x + \log_a y \\
\log_a (\frac{x}{y})=\log_a x - \log_a y \\
\log_a (x^n)n \log_a x$

Expand the expression:
$\log_b (\frac{m^2n}{p})=\log_b m^2 + \log_b n - \log_b p= 2 \log_b m+\log_b n - \log_b p$

Plug the values into the expression:
$\log_b m=3.2 \\ \log_b n=-1.5 \\ \log_b p=2.4 \\ \\
2 \log_b m+\log_b n - \log_b p=2 \times 3.2-1.5-2.4=6.4-3.9=2.5 \\ \\
\boxed{\log_b (\frac{m^2n}{p})=2.5}$

3 0

3 years ago

Which of the tables does NOT represent a function ?

strojnjashka [21]

Answer:

Step-by-step explanation:

My teacher used to compare functions to vending machines, if i press 2 then i will get m&m's which is 6. But if I press 3 I can't get m&m's(6) and a candy bar which is 7. Hope this helped.

4 0

3 years ago

13/20 , 11/15 , 5/8, 7/12 from least to greatest

Sveta_85 [38]

Answer:

Least 2 Greatest:

7/12, 5/8, 13/20, 11/15

Step-by-step explanation:

Googled it

Plz say thxs and rate me!

Yours Truly.

5 0

3 years ago

Convert the following sum into a product. cosx + cos3x + cos5x + cos7x

kvv77 [185]

Answer:

$4\cos x\cos (4x)\cos (2x)$

Step-by-step explanation:

Given: $cosx + cos3x + cos5x + cos7x$

To convert: the given sum into product

Solution:

Use formula: $\cos A+\cos B=2\cos \left ( \frac{A+B}{2} \right )\cos \left ( \frac{A-B}{2} \right )$

$cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos (2x)\cos (-x)+2\cos (6x)\cos (-x)\\=2\cos (2x)\cos (x)+2\cos (6x)\cos (x)\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]$

$cosx + cos3x + cos5x + cos7x=2\cos \left ( \frac{x+3x}{2} \right )\cos \left ( \frac{x-3x}{2} \right )+2\cos \left ( \frac{5x+7x}{2} \right )\cos \left ( \frac{5x-7x}{2} \right )\\=2\cos x\left [ \cos (2x)+\cos (6x) \right ]\\=2\cos x\left [2 \cos \left ( \frac{2x+6x}{2} \right )\cos \left ( \frac{2x-6x}{2} \right ) \right ]\\=2\cos x\left [ 2\cos (4x) \cos (-2x) \right ]\\=4\cos x\cos (4x)\cos (2x)$

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3 years ago

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Vadim26 [7]

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3 years ago