Answer:
a) 0.59871
b) 0.22663
e) 0.95994
Step-by-step explanation:
The height of adult males on a given South Pacific Island is approximately normally distributed with mean 65 inches and standard deviation of 4 inches.
We solve using z score
z = (x-μ)/σ, where
x is the raw score
μ is the population mean = 65 inches
σ is the population standard deviation = 4 inches
a). Taller than 64 inches
This means x > 64
Hence,
64 - 65/4
=- 1/4 = -0.25
P-value from Z-Table:
P(x<64) = 0.40129
P(x>64) = 1 - P(x<64) = 0.59871
b.) shorter than 62 inches
Hence,
62 - 65/4
=- 3/4 =- 0.75
P-value from Z-Table:
P(x<62) = 0.22663
c.) between 64 inches and 68 inches
Hence,
for 64 inches
64 - 65/4
=- 1/4 = -0.25
P-value from Z-Table:
P(x = 64) = 0.40129
For 68 inches
Hence,
68 - 65/4
= 3/4= 0.75
P-value from Z-Table:
P(x = 68) = 0.77337
d.) between 58 and 68 inches
e.) taller than 58 inches
Hence,
58 - 65/4
= -6/4 = -1.5
P-value from Z-Table:
P(x<58) = 0.040059
P(x>58) = 1 - P(x<58) = 0.95994
