Answer:
the largest angle of the field is 149⁰
Step-by-step explanation:
Given;
perimeter of the triangular filed, P = 120 m
length of two known sides, a and b = 21 m and 40 m respectively
The length of the third side is calculated as follows;
a + b + c = P
21 m + 40 m + c = 120 m
61 m + c = 120 m
c = 120 m - 61 m
c = 59 m
B
↓ ↓
↓ ↓
↓ ↓
A → → → → → → → → → → → C
Consider ABC as the triangular field;
Angle A is calculated by applying cosine rule;

Angle B is calculated as follows;

Angle C is calculated as follows;

Therefore, the largest angle of the field is 149⁰.
Answer:
4
Step-by-step explanation:
Is that a log with the base of 3√(2) ?
If so....my calculator says the answer is 4
Let's see if we can do it w/ou the calculator:
3 sqrt(2)^x = 324 = 3^4 * 2^2 Now 'LOG' both sides:
x log (3 sqrt 2) = log (3^4 *2^2) = 4 log ( 3 * 2^(2/4)) = 4 log (3 sqrt2)
now divide both sides by log (3 sqrt2 )
x = 4 (If I did the math correctly ! )
B I think not sure ......
XZ=XY+YZ
JL=JK+KL
use the trigonometric values table or unit circle to calculate the expression