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3 years ago

Haven't run across one with three terms. help? preferably explain how you got the answer too!!

Mathematics

1 answer:

const2013 [10]3 years ago

5 0

Answer:

c^3 + c^2 - 7c + 20

Step-by-step explanation:

First, expand the expression using distributive property.

c^2(c+4) - 3c(c+4) + 5(c+4)

c^3 + 4c^2 - 3c^2 - 12c + 5c + 20

Lastly, simplify like terms.

c^3 + c^2 - 7c + 20

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Finger [1]

Using the midpoint formula, the coordinates of endpoint H are (4, -6).

<h3>The Midpoint Formula</h3>

The midpoint formula is given as: $(x_m, y_m) = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} )$

<em>Where</em>,

$(x_m, y_m)$ = coordinates of the midpoint

$(x_1, y_1)$ = coordinates of the first point

$(x_2, y_2)$ = coordinates of the second point

Given the following:

$(x_m, y_m)$ = M( 6,-4)

$(x_1, y_1)$ = G(8,-2)

$(x_2, y_2)$ = H(?, ?)

Plug in the values into the midpoint formula

$M(6, -4) = (\frac{8 + x_2}{2}, \frac{-2 + y_2}{2} )$

Solve for the x-coordinate and y-coordinate separately

$6 = \frac{8 + x_2}{2}$

Multiply both sides

$6 \times 2 = 8 + x_2\\\\12 = 8 + x_2\\\\12 - 8 = x_2\\\\4 = x_2\\\\\mathbf{x_2 = 4}$

$-4 = \frac{-2 + y_2}{2}\\\\-8 = -2 + y_2\\\\-8 + 2 = y_2\\\\-6 = y_2\\\\\mathbf{y_2 = -6}$

Therefore, using the midpoint formula, the coordinates of endpoint H are (4, -6).

Learn more about midpoint formula on:

brainly.com/question/13115533

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2 years ago

Haven't run across one with three terms. help? preferably explain how you got the answer too!!​

Haven't run across one with three terms. help? preferably explain how you got the answer too!!