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3 years ago

5

Haven't run across one with three terms. help? preferably explain how you got the answer too!!

1 answer:

const2013 [10]3 years ago

5 0

Answer:

c^3 + c^2 - 7c + 20

Step-by-step explanation:

First, expand the expression using distributive property.

c^2(c+4) - 3c(c+4) + 5(c+4)

c^3 + 4c^2 - 3c^2 - 12c + 5c + 20

Lastly, simplify like terms.

c^3 + c^2 - 7c + 20

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Six added to 3 times a number is equal to 4 less than 5 times the number. What is the number?

harina [27]

Answer:

$5$

Step-by-step explanation:

Let the number be $x$ .

$3x+6=5x-4$

$3x-5x=-4-6$

$-2x=-10$

$2x=10$

$2x/2=10/2$

$x=5$

The number is 5.

8 0

3 years ago

Read 2 more answers

For the equation Y= 2(x+4)-3 what ordered pair what are used to start a graphing PLEASEEEE HELP

Anton [14]

Answer:

(4,-3)

Step-by-step explanation:

6 0

3 years ago

Boris choos three diffrent numbers.the sum of the three numbers is 36.One of trh numbers is a cube number.the other two number a

inna [77]

Answer:

4,5,27

Problem:

Boris chose three different numbers.

The sum of the three numbers is 36.

One of the numbers is a perfect cube.

The other two numbers are factors of 20.

Step-by-step explanation:

Let's pretend those numbers are:

$a,b, \text{ and } c$ .

We are given the sum is 36: $a+b+c=36$ .

One of our numbers is a perfect cube. $a=n^3$ where $n$ is an integer.

The other two numbers are factors of 20. $bk=20$ and $ci=20$ where $a,c,i, \text{ and } k \text{ are integers}$ .

$n^3+\frac{20}{k}+\frac{20}{i}=36$

From here I would just try to find numbers that satisfy the conditions using trial and error.

$3^3+\frac{20}{2}+\frac{20}{2}$

$27+10+10$

$47$

$3^3+\frac{20}{4}+\frac{20}{5}$

$27+5+4$

$36$

So I have found a triple that works:

$27,5,4$

The numbers in ascending order is:

$4,5,27$

4 0

3 years ago

2. Which of the following phrases means "is not greater than or equal to"?

ruslelena [56]

I'm pretty sure it would be "is at most" "is less than" and "does not exceed"

7 0

3 years ago

Ethan bought 4 packages of pencils. After he gave 8 pencils to his friends, he had 40 pencils

LiRa [457]

He had 40 pencils left after he gave away 8, so originally he had 40 + 8 pencils, which is 48.

Now, he bought 4 packages, which had a total of 48 pencils, so divide 48 by 4, which is 12. He had 12 pencils in each package.

To determine the solution arithmetically, first add 8 to 40, then divide 48 by 4.

To determine the solution algebraically, set up and solve the equation 40 = 4x - 8.

Each package contained 12 pencils.

Hope this helps

8 0

3 years ago