Should be the second one.
Answer:
<h2>
70cm/s</h2>
Step-by-step explanation:
Area of a square with side of length L is expressed as A = L². The rate at which the area is increasing will be expressed as dA/dt.
dA/dt = dA/dL * dL/dt where
dL/dt is the rate at which each side of the square is increasing.
Since dA/dL = 2L, dA/dt = 2L dL/dt
Given dL/dt = 5cm/s and the Area of the square = 49 cm²
49 = L²
L = √49
L = 7cm
dA/dt = 2(7) * 5
dA/dt = 14*5
dA/dt = 70cm/s
The rate at which the area of the square is increasing is 70cm/s
Answer:
This would be a reflection over the x-axis and a vertical stretch by a factor of 3.
Step-by-step explanation:
We can identify the shift over the x-axis by looking at the negative in the front.
We can identify the vertical stretch by noting that the variable is being multiplied by 3, which makes the y value go up 3 times as fast.
Answer: b= -8
Step-by-step explanation:
Eleven is 10 and twelve is A, D, and E.
