2 years ago

Solve

1 answer:

4 0

Answer:

Step-by-step explanation:

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Bess [88]

With $x(t)=\cos t$ and $y(t)=\sin t$ , we have

$z(t)=x(t)^2+4y(t)^2+1$

$z(t)=\cos^2t+4\sin^2t+1$

$z(t)=3\sin^2t+2$

Then $z(t)$ has critical points where

$\dfrac{\mathrm dz}{\mathrm dt}=6\sin t\cos t=3\sin2t=0$

$\implies\sin2t=0\implies2t=n\pi\implies t=\dfrac{n\pi}2$

where $n$ is any integer.

$z(t)$ is increasing wherever $\sin2t>0$ , which happens for

$\dfrac{2n\pi}2$

$\boxed{n\pi$

5 0

2 years ago

Svet_ta [14]

After 5 hours is the correct answer

8 0

2 years ago

victus00 [196]

I think the answer is B not sure though

7 0

2 years ago

vovangra [49]

Where’s your picture?

5 0

2 years ago

garik1379 [7]

Answer:

1/5n-8<_96

Step-by-step explanation:

8 0

3 years ago