A coyote had 10 pups in her third litter. (10)
It was twice as many as in her second litter,( 2( second litter) = third litter
her second litter had 3 more pups than her first.( first litter +3)=2nd litter
Find the number of pups in her litter
It looks like ∆ is defined as
<em>a</em> ∆ <em>b</em> = (<em>a</em> + <em>b</em>)² + 5
If that's the case, then
1 ∆ (-4) = (1 + (-4))² + 5 = (-3)² + 5 = 9 + 5 = 14
I believe the number is 406,152
Sides that two side is equal so
5x+10=40
5x=30
X=6