Given:
Point is T(-3,8).
To find:
The coordinates of T' after
.
Solution:
We know that,
means the figure reflected across the x-axis then reflected across y-axis.
If a figure reflected across x-axis, then


If a figure reflected across y-axis, then



Therefore, the required point is T'(3,-8).
Is there a fraction or a number line to explain you question?☺
Answer:
Part A)
The equation in the point-slope form is:

Part B)
The graph of the equation is attached below.
Step-by-step explanation:
Part A)
Given
The point-slope form of the line equation is

Here, m is the slope and (x₁, y₁) is the point
substituting the values m = 4/3 and the point (-2, 11) in the point-slope form of the line equation


Thus, the equation in the point-slope form is:

Part B)
As we have determined the point-slope form which passes through the point (-2, 11) and has a slope m = 4/3
The graph of the equation is attached below.
Answer:
x=4 y=1
x=4 y=4
Step-by-step explanation:
x=4 goes on plot 4
(4,f(4)) plot goes on 4 x, 4 and y, 4
hope this helps