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77julia77 [94]
3 years ago
5

What is the volume of a cube with 2 1/4 inch sides

Mathematics
1 answer:
eduard3 years ago
8 0

Answer:11.39

Step-by-step explanation:

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In the bridge below , AABC~AXYZ.If AB=AC=25 feet,BC=20 feet,and YZ=10 feet, then what is XZ?
labwork [276]

Answer:

I think It's A).25 ft.

Step-by-step explanation:

I d k if I'm right but I tried btw I hope it helps

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2 years ago
What is the slope of the line through (−1,−7) and (3,9)?
Alona [7]

Answer:

The slope is 4.

Step-by-step explanation:

Point slope form is y-y1 over x-x1. I put the coordinates in like this.

9-(-7) over 3-(-1) so thats 9+7 over 3+1. 16 over 4 is 4.

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3 years ago
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-120 = -8x what is x ?
lora16 [44]

Answer:

- 15 is your answer.

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3 years ago
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DaniilM [7]
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4 years ago
In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.
jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}

\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}

\text{The weight of average pumpkin}=5\text{ kg}

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0
4 years ago
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