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3 years ago

What is the volume of a cube with 2 1/4 inch sides

Mathematics

1 answer:

eduard3 years ago

8 0

Answer:11.39

Step-by-step explanation:

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If x = 6, what is the value of 4x2 - 7? O A. 151 B. 137 C. 571 D. 172

aalyn [17]

Answer: B

Step-by-step explanation: 6^2 = 36

36*4= 144

144-7= 137

5 0

3 years ago

Read 2 more answers

Write the equation of the line that passes. Throught the point (-2,1)and (0,8)put your aswer in fully reduce point slope form un

Soloha48 [4]

Answer:

Step-by-step explanation:

first, we need to find the slope

slope = (y2 - y1) / (x2 - x1)

(-2,1)...x1 = -2 and y1 = 1

(0,8)...x2 = 0 and y2 = 8

now sub

slope = (8 - 1) / (0- (-2) = 7/(0 + 2) = 7/2

point slope form : y - y1 = m(x - x1)

using point (-2,1)....x1 = -2 and y1 = 1

slope(m) = 7/2

now sub

y - 1 = 7/2(x - (-2) =

y - 1 = 7/2(x + 2) <==== here is one answer

y - y1 = m(x - x1)

using point (0,8)...x1 = 0 and y1 = 8

slope(m) = 7/2

now sub

y - 8 = 7/2(x - 0) <===== another possible answer

6 0

3 years ago

Simplify (-343,000) 1/3

bixtya [17]

-343,000 x 1/3 = -114,333.333333333219

3 0

3 years ago

How much money will you have if you started with $1250 and put it in an account that earned 6.7% every year for 14 years?

KatRina [158]

Answer:

$3098.93

Step-by-step explanation:

We can use the formula for compound growth to solve this. The formula is:

$F=P(1+r)^t$

Where

F is the future value (the value at end of 14 years, our answer)

P is the initial amount invested ($1250)

r is the interest rate, in decimal (6.7% is 0.067)

t is the time in years (14, in our case)

Plugging in all the information we have:

$F=P(1+r)^t\\F=1250(1+0.067)^14\\F=1250(1.067)^14\\F=3098.93$

The account will accrue $3098.93 after 14 years.

3 0

3 years ago

The perimeter of a rectangle garden is 364 feet. If the width of the garden is 85 feet, what is it length?

kherson [118]

P=2(L+W)

P=364

L=99

sub and find W

364=2(99+W)

divide both sides by 2

182=99+w

subtract 99 from both sides

83=W

w=83ft

6 0

2 years ago