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scoray [572]
3 years ago
6

Is a home loan closed end credit

Mathematics
1 answer:
Alona [7]3 years ago
6 0

Answer:

Closed-end credit is a type of credit that should be repaid in full amount by the end of the term, by a specified date. The repayment includes all the interests and financial charges agreed at the signing of the credit agreement. Closed-end credits include all kinds of mortgage lending and car loans.

Step-by-step explanation:

Does this help, sir?

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A *divide sign* isn't closed since there isn't a second letter or number with it
5 0
3 years ago
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Artist 52 [7]
The third answer is correct.
5 0
4 years ago
The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.
Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0
3 years ago
Un dispositivo de seguridad biométrico erróneamente rechaza la admisión de 1 en 1000 personas autorizadas de una instalación que
Leona [35]

Usando probabilidad condicional, se encuentra que hay una probabilidad de 0.0186 = 1.86% que la persona esta realmente autorizada para ingresar.

------------------

Probabilidad Condicional

P(B|A) = \frac{P(A \cap B)}{P(A)}

En que:

  • P(B|A) es la probabilidad de que ocurra el evento B, dado que A sucedió.  
  • P(A \cap B) es la probabilidad de que ocurran tanto A como B.  
  • P(A) es la probabilidad de que ocurra el evento A.

En este problema:

  • Evento A: Persona rechazada.
  • Evento B: Autorizada.

La probabilidad de una persona ser rechazada es:

  • \frac{1}{1000} = 0.001 de 95% = 0.95(autorizada).
  • \frac{1 000 000 - 1}{1 000 000} = 0.999999 de 5% = 0.05(non autorizadas).

O sea:

P(A) = 0.001(0.95) + 0.999999(0.05) = 0.05094995&#10;

La probabilidad de una persona estar autorizada y ser rechazada es:

P(A \cap B) = 0.001(0.95)

¿Cuál es la probabilidad que la persona esta realmente autorizada para ingresar?

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(B|A) = \frac{0.001(0.95)}{0.05094995}

P(B|A) = 0.0186

Probabilidad de 0.0186 = 1.86% que la persona esta realmente autorizada para ingresar.

Un problema similar es dado en brainly.com/question/18734831

3 0
3 years ago
I give brainliest pls answer
mojhsa [17]

Answer:

The answer is <u>x = 65 - 60y.</u>

Step-by-step explanation

3 0
3 years ago
Read 2 more answers
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