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3 years ago

3x+2y=4 2x-y=5

Mathematics

2 answers:

Ann [662]3 years ago

8 0

Answer:

B. Has one solution

Step-by-step explanation:

It can be solved simultaneously to get the values of x and y

Sunny_sXe [5.5K]3 years ago

7 0

Answer:

Step-by-step explanation:

it only has one solution

You might be interested in

Use the table to write a linear function that relates y to x.

blsea [12.9K]

Answer:

y = - $\frac{2}{3}$ x

Step-by-step explanation:

the equation of a linear function in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 8, 2) and (x₂, y₂ ) = (1, - 4) ← 2 ordered pairs from the table

m = $\frac{-4-2}{1-(-8)}$ = $\frac{-6}{1+8}$ = $\frac{-6}{9}$ = - $\frac{2}{3}$

the ordered pair (0, 0 ) indicates the line crosses through the origin, then

c = 0

y = - $\frac{2}{3}$ x + 0 , that is

y = - $\frac{2}{3}$ x ← equation of linear function

4 0

2 years ago

A ship at position (1, 0) on a nautical chart (with north in the positive y direction) sights a rock at position (7, 5). What an

Romashka-Z-Leto [24]

Answer:

0.69473828 radians east of north.

Step-by-step explanation:

Interpreting the information given on a Cartesian plane, the position of the ship will be (1,0) and that of the rock will be (7,5). Connecting the point (1,0) and (7,5) with a line and dropping a perpendicular line from point (7,5) to the x-axis to intersect the x-axis at (7,0), will form a right-triangle with base length 6 units and a height of 5 units.

<u>Finding the base length from points (1,0) and (7,0)</u>

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(7-1)²

d= √6²

d=6 units

<u>Finding the height from points (7,5) and (7,0)</u>

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(7-7)² + (0-5)²

d=√-5²

d=√25

d=5 units

So you now have a right triangle with base length 6 units and height 5 units.

To get the bearing of rock from ship position you apply the formula for tangent of an angle

Tan Ф = length of opposite side/length of adjustment side

TanФ=5/6

Tan Ф =0.83333333333

Tan⁻¹ (0.83333333333) =0.69473828 radians east of north.

3 0

3 years ago

Select all the points that are on the graph of the line 2x + 4y=20 a.)(0.5) b. (0,10) c. (1,2) d.) (1,4) e.) (5,0) f. (10,0)

zmey [24]

Answer:

(0,5) and (10,0)

Step-by-step explanation:

The equation of the straight line is given by 2x + 4y = 20 .......... (1)

Now, point (0,5) satisfies the equation (1) as putting x = 0, we will get y = 5.

Now, point (0,10) does not satisfy the equation (1) as putiing x = 0, we get y = 5 ≠ 10

Again, point (1,2) does not satisfy the equation (1) as putiing x = 1, we get y = 4.5 ≠ 2

Now, point (1,4) does not satisfy the equation (1) as putiing x = 1, we get y = 4.5 ≠ 4

Again, point (5,0) does not satisfy the equation (1) as putiing y = 0, we get x = 10 ≠ 5

Finally, point (10,0) satisfies the equation (1) as putiing y = 0, we get x = 10 .

Therefore, only points (0,5) and (10,0) are on the graph of the line 2x + 4y = 20 (Answer)

8 0

3 years ago

The oblique prism below has an isosceles right triangle base. An oblique right triangular prism is shown. The triangular bases h

balandron [24]

The volume of the geometry that is oblique prism is $\rm 0.5x^3 + x^2$ . Then the correct option is A.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

Given

The oblique prism below has an isosceles right triangle base.

The triangular bases have 2 sides with a length of x.

The distance from the 2 triangular bases is (x + 3).

The vertical height of the prism is (x + 2).

The volume of the oblique prism will be

$\rm Volume = Area\ of \ triangle * Vertical\ Height \\\\Volume = \dfrac{1}{2} (Base)^2 * Vertical \ Hetght\\\\Volume = \dfrac{1}{2} x^2 (x + 2)\\\\Volume = \dfrac{1}{2} x^3 + x^{2} \\\\$