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2 years ago

The aos of x=2?????????

Mathematics

1 answer:

VLD [36.1K]2 years ago

5 0

You are correct,
also don’t click on that file the person above me
put

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For the function F(x) = 1/x+2, which of these could be a value of F(x) when xis

hram777 [196]

Answer:

B 2

Step-by-step explanation:

The computation of the value of f(x) in the case when x = 2 is shown below

As per the question, following function is given

F(x) = (1 ÷ x) + 2

Based on this, the x = 2

Now put the x value in the above equation

So,

= (1 ÷ 2) + 2

= (1 + 4) ÷ 2

= 5 ÷ 2

= 2.5

Hence the closet number is 2

Therefore the value of f(x) in the case when x = 2 is 2

Hence, the correct option is b.

5 0

3 years ago

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H(x)= 9/x( x^2-49)<br> Determine the domain of the function

Norma-Jean [14]

Answer: The domain of the function $h(x) = \frac{9}{x(x^2-49)}$ is:

Interval Notation: (-∞ , -7) ∪ (-7 , 0) ∪ (0 , 7) ∪ (7, ∞)

Set-Builder Notation: { x | x ≠ 0 , 7 , -7 }

All real numbers besides 0, 7, and -7.

Step-by-step explanation:

In order to find the domain of your rational function, we need to simplify it:

$h(x) = \frac{9}{x(x^2-49)} = \frac{9}{(x)(x+7)(x-7)}$

Remember, most of the time, the domain of a rational function consists of all real numbers besides zero.

To find the domain, we equal the equations in the denominator to zero.

$x=0$

$x+7=0$ --> $x=-7$

$x-7=0$ --> $x=7$

So all real numbers except for 0, -7, and 7 are in the domain of this rational function.

8 0

3 years ago

Simplify ( 1/2A + 1/2B )^2

zysi [14]

Notice that both A and B are multiplied by (1/2).

Thus, the given expression can be re-written as [(1/2)(A+B)]^2.

Square the (1/2) and the (A+B) separately, and then multiply together the resulting squares:

(1/4)(A^2 + 2AB + B^2)

4 0

3 years ago

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9. One winter day, the temperature increased

Andru [333]

Answer: A~ 45

Step-by-step explanation:

8 0

3 years ago

Give all solutions if the nonlinear system of equations, including those with no real complex components.

konstantin123 [22]

$\left\{\begin{array}{ccc}y=x^2+6x\\4x-y=-24\end{array}\right\\\\substitute:\\\\4x-(x^2+6x)=-24\\\\4x-x^2-6x+24=0\\\\-x^2-2x+24=0\\\\a=-1;\ b=-2;\ c=24\\\\\Delta=b^2-4ac$

$\Delta=(-2)^2-4\cdot(-1)\cdot24=4+96=100\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{100}=10\\\\x_1=\frac{2-10}{2\cdot(-1)}=\frac{-8}{-2}=4;\ x_2=\frac{2+10}{2\cdot(-1)}=\frac{12}{-2}=-6\\\\y_1=4^2+6\cdot4=16+24=40;\ y_2=(-6)^2+6\cdot(-6)=36-36=0\\\\Answer:\\x=4\ and\ y=40\ or\ x=-6\ and\ y=0$

4 0

3 years ago

Read 2 more answers