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musickatia [10]
3 years ago
8

What is the value of x in the rhombus below?

Mathematics
2 answers:
GuDViN [60]3 years ago
7 0

Answer:

Option C

21\°

Step-by-step explanation:

we know that

The two diagonals of a rhombus are perpendicular

so

Let

O------> the center of the rhombus

m∠AOB=90\°

Remember that

The sum of the internal angles of a triangle is equal to 180\°

therefore

in the triangle AOB

m∠AOB+m∠OAB+m∠OBA=180\°

substitute the values

90\°+(2x+1)\°+(2x+5)\°=180\°

solve for x

(4x+6)\°=90\°

4x=90\°-6\°

x=21\°

Maurinko [17]3 years ago
5 0
Look into my attachment

in rhombus ABCD, ∠AOB = 90°

Look at ΔAOB
the sum of inner angles = 180°
∠BAO + ∠AOB + ∠ABO = 180°
2x + 1 + 90 + 2x + 5 = 180°
4x + 96 = 180
4x = 84
x = 21

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