What is the value of x in the rhombus below?
2 answers:
Answer:
Option C

Step-by-step explanation:
we know that
The two diagonals of a rhombus are perpendicular
so
Let
O------> the center of the rhombus
m∠AOB=
Remember that
The sum of the internal angles of a triangle is equal to 
therefore
in the triangle AOB
m∠AOB+m∠OAB+m∠OBA=
substitute the values

solve for x



Look into my attachment
in rhombus ABCD, ∠AOB = 90°
Look at ΔAOBthe sum of inner angles = 180°
∠BAO + ∠AOB + ∠ABO = 180°
2x + 1 + 90 + 2x + 5 = 180°
4x + 96 = 180
4x = 84
x = 21
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