Question

Please help!!! Work out the surface area for this solid prism.

Answer 1

Answer:

3060 $cm^{2}$

Step-by-step explanation:

Find the cross-sectional area first of the trapezium

$\frac{1}{2} (a+b)h$

So,  $\frac{1}{2}(6+34)15$

which is 40 / 2 x 15 = 20 x 15 = 300 $cm^{2}$

Since there are 2 trapeziums (on the front and back): 300 x 2 = 600$cm^{2}$

Find the Area of the Rectangles

The first rectangle on the top would be: 6x30 = 180 $cm^{2}$

The slanted rectangle on the right would be: 25x30 = 750 $cm^{2}$

The rectangle on the bottom would be: 30x34 = 1020 $cm^{2}$

The hidden rectangle on the left would be: 17 x 30 = 510 $cm^{2}$

So by combining all these calculations, you will get the total surface area which is:

600 + 180 + 750 + 1020 + 510 = 780 + 1770 + 510 = 2550 + 510 = 3060 $cm^{2}$