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babymother [125]

2 years ago

10

A jug of juice has 6 cups of pineapple juice and 5 cups of orange juice. Write the ratio of the number of cups of pineapple juic

e to total number of cups of juice in three different ways.

1 answer:

REY [17]2 years ago

6 0

Answer:

number of cups of pineapple to total number of cups...

6:11 or 6/11 or 6 to 11

Step-by-step explanation:

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How do you do square roots totem pole

Igoryamba

Well the square root of a number is a number times its self equaling the number you're getting the square root of. For example:

<span>√ 25
</span>
To get sqrt of 25 we need to find a number times its self that equals 25. Lets try 8.

8 x 8 = 64

Well thats much too high, We'll try a lower number.

4 x 4 = 16

Just a little higher.

5 x 5 = 25

Since 5 times itself equals 25 that makes it the sqrt.

So, the √ 25 is 5.

7 0

3 years ago

Can one of y’all help me pls

swat32

Answer:

D) x - 7 + 3

Step-by-step explanation:

gave sister = subtract

aunt gave = addition

Equation:

x - 7 + 3

7 0

3 years ago

Find the area of the rectangle.

aev [14]

Answer:

$69y+23$

Step-by-step explanation:

The area of a rectangle will always be length times width or width times length, doesn't matter which way.

In this case, the width is $3y+1$ miles and the length is $23$ miles. So, the area is $23(3y+1)=23*3*y+23*1=69*y+23$ .

So, the area is $\boxed{69y+23}$ and we're done.

3 0

2 years ago

.chris p. bacon worked 44 hours last week and gets double time pay for overtime. his regular pay is $14 per hour. how much was h

masha68 [24]

The total paycheck for the week is of $672 as Chris bacon work for 44 hours last week, regular pay $14 per hour and double time pay for overtime.

As given,

Regular pay per hour = $14

Overtime work payment= 2 × ($14)

Total hours work done last week = 44hours

Let regular timing be 8 hours per day 5 days a week

Total regular working hours = 8 × 5

= 40 hours

Over time = 44-40

= 4 hours

Payment check = (40 × 14)+ (4 × 28)

= $672

Therefore, The total paycheck for the week is of $672 as Chris bacon work for 44 hours last week.

Learn more about work here

brainly.com/question/18094932

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8 0

1 year ago

How do I solve: 2 sin (2x) - 2 sin x + 2√3 cos x - √3 = 0

ziro4ka [17]

Answer:

$\displaystyle x = \frac{\pi}{3} +k\, \pi$ or $\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ , where $k$ is an integer.

There are three such angles between $0$ and $2\pi$ : $\displaystyle \frac{\pi}{3}$ , $\displaystyle \frac{2\, \pi}{3}$ , and $\displaystyle \frac{4\,\pi}{3}$ .

Step-by-step explanation:

By the double angle identity of sines:

$\sin(2\, x) = 2\, \sin x \cdot \cos x$ .

Rewrite the original equation with this identity:

$2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0$ .

Note, that $2\, (2\, \sin x \cdot \cos x)$ and $(-2\, \sin x)$ share the common factor $(2\, \sin x)$ . On the other hand, $2\sqrt{3}\, \cos x$ and $(-\sqrt{3})$ share the common factor $\sqrt[3}$ . Combine these terms pairwise using the two common factors:

$(2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0$ .

Note the new common factor $(2\, \cos x - 1)$ . Therefore:

$\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0$ .

This equation holds as long as either $\left(2\, \sin x + \sqrt{3}\right)$ or $(2\, \cos x - 1)$ is zero. Let $k$ be an integer. Accordingly:

$\displaystyle \sin x = -\frac{\sqrt{3}}{2}$ , which corresponds to $\displaystyle x = -\frac{\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = -\frac{2\, \pi}{3} + 2\, k\, \pi$ .
$\displaystyle \cos x = \frac{1}{2}$ , which corresponds to $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ and $\displaystyle x = -\frac{\pi}{3} + 2\, k \, \pi$ .

Any $x$ that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:

$\displaystyle x = \frac{\pi}{3} + k \, \pi$ (from $\displaystyle x = -\frac{2\,\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ , combined,) as well as
$\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ .

7 0

3 years ago