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Keith_Richards [23]

2 years ago

7

Bjorn wants to save $1,680 so that he can buy the car he wants. If Bjorn can save $15 per day, how many days will it take him to

save enough money?

1 answer:

Marta_Voda [28]2 years ago

5 0

$1680/$15= 112 days

It will take 112 days.

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A biologist is researching a newly-discovered species of bacteria. He puts 1,000 bacteria into what he has determined to be a fa

Svetradugi [14.3K]

The bacteria grow from <span>1,000 bacteria into 12,500 bacteria in 12 hours. The exponent function would be:

an= ao(1+r)^t
12.500= 1,000(1+r)^12
1,000(12.5)= 1,000(1+r)^12
</span>12.5= (1+r)^12
1+r= 1.23427
r= 0.23

Number of bacteria after 20hr would be:
an= ao(1+r)^t
an= 1,000(1+0.23)^20
an= 1,000(62.821 <span>)
an= </span><span>62,821 </span>

7 0

3 years ago

Identify the expression with nonnegative limit values. More info on the pic. PLEASE HELP.

marshall27 [118]

Answer:

$\lim _{x\to 2}\:\frac{x-2}{x^2-2}\\\\ \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}\\\\ \lim _{x\to \frac{5}{2}}\left\frac{2x^2+x-15}{2x-5}\right$

Step-by-step explanation:

a) $\lim _{x\to 3}\:\frac{x^2-10x+21}{x^2+4x-21}=\lim \:_{x\to \:3}\:\frac{\left(x-7\right)\left(x-3\right)}{\left(x+7\right)\left(x-3\right)}=\lim \:_{x\to \:3}\:\frac{x-7}{x+7}=\frac{3-7}{3+7}=-\frac{4}{10}=-\frac{2}{5}$

b) $\lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=\lim \:_{x\to -\frac{3}{2}}\:\frac{\left(2x+3\right)\left(x-4\right)}{\left(2x+3\right)}=\lim \:\:_{x\to \:-\frac{3}{2}}\:\left(x-4\right)=-\frac{3}{2}-4\\ \\ \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=-\frac{11}{2}$

c) $\lim _{x\to 2}\:\frac{x-2}{x^2-2}=\frac{2-2}{\left(2\right)^2-2}=\frac{0}{4-2}=0$

d) $\lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}=\lim _{x\to 11}\:\frac{\left(x-11\right)\left(x+17\right)}{\left(x-11\right)\left(x+14\right)}=\lim _{x\to 11}\:\frac{\left(x+17\right)}{\left(x+14\right)}=\frac{11+17}{11+14}=\frac{28}{25}$

e) $\lim _{x\to 3}\:\frac{x^2-8x+15}{x-3}=\lim \:_{x\to \:3}\:\frac{\left(x-3\right)\left(x-5\right)}{x-3}=\lim _{x\to 3}\left(x-5\right)=3-5=-2$

f) $\lim _{x\to \frac{5}{2}}\left(\frac{2x^2+x-15}{2x-5}\right)=\lim \:_{x\to \:\frac{5}{2}}\frac{\left(2x-5\right)\left(x+3\right)}{2x-5}=\lim \:\:_{x\to \:\:\frac{5}{2}}\left(x+3\right)=\frac{5}{2}+3=\frac{11}{2}$

4 0

3 years ago

Which expression is equivalent to 4 - (-7

liraira [26]

Answer:

11 is the answer

Step-by-step explanation:

4 0

2 years ago

Vera ordered a soup, salad, and sandwich to share with her friends. The probabilities of each item being ready

Mkey [24]

Answer:

its

Soup ready first

Sandwich ready first

Salad ready first

Step-by-step explanation:

7 0

3 years ago

Solve the equation for x.<br> x<br> 9<br> =

iren [92.7K]

What kind of operation is this ? it just says x and a nine.

3 0

2 years ago