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JulijaS [17]
2 years ago
7

Which is the product of 7/9 and 6? A. 1 4/9 B. 3 7/9 C. 4 2/3 D. 7 5/7

Mathematics
2 answers:
Vladimir79 [104]2 years ago
8 0

Answer:

C. 4 2/3

Step-by-step explanation:

1) Use this rule: a/b * c = ac/b.

7 * 6/9

2)  Simplify 7 * 6 to 42.

42/9

3) Simplify.

14/3

4) Convert to mixed fractin form.

4 2/3

lora16 [44]2 years ago
4 0

Answer:

The product of 7/9 and 6:

\\7/9 x 6 \\\\7x6=42\\\\42/9\\4 6/9\\\\4 is the whole number\\6/9 is the fraction that if we remove the 3 from both of us, it gives us the result 2/3\\ The answer is the B \\

Step-by-step explanation:

the answer is the B

Because You only had to multiply 6 by 7 and the result, which would be 42 over 9, should be converted to a mixed number, which would be dividing 42 by 9, which is 4, and us over 6, which is four, which is the whole number, and 6 is the numerator and you don't change the nine since it is still the denominator.

Because the 4 is the whole number

And 6/9 is the fraction that if were move the 3 from both of us , it gives us the result is 2/3

So we have 4 2/3

the answer is the B

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Part 1) Australia 19,751,012\ people

Part 2) China 1,319,645,764\ people

Part 3) Mexico 109,712,539\ people

Part 4) Zaire 60,534,681\ people

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

P(t)=a(1+r)^t

where

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we have

a=19,169,000\\r=0.6\%=0.6\100=0.006

substitute

P(t)=19,169,000(1+0.006)^t

P(t)=19,169,000(1.006)^t

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substitute the value of t in the equation

P(5)=19,169,000(1.006)^5=19,751,012\ people

Part 2) China

we have

a=1,261,832,000\\r=0.9\%=0.9\100=0.009

substitute

P(t)=1,261,832,000(1+0.009)^t

P(t)=1,261,832,000(1.009)^t

Find the  expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people

Part 3) Mexico

we have

a=100,350,000\\r=1.8\%=1.8\100=0.018

substitute

P(t)=100,350,000(1+0.018)^t

P(t)=100,350,000(1.018)^t

Find the  expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

P(5)=100,350,000(1.018)^5=109,712,539\ people

Part 4) Zaire

we have

a=51,965,000\\r=3.1\%=3.1\100=0.031

substitute

P(t)=51,965,000(1+0.031)^t

P(t)=51,965,000(1.031)^t

Find the  expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

P(5)=51,965,000(1.031)^5=60,534,681\ people

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