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JulijaS [17]
2 years ago
7

Which is the product of 7/9 and 6? A. 1 4/9 B. 3 7/9 C. 4 2/3 D. 7 5/7

Mathematics
2 answers:
Vladimir79 [104]2 years ago
8 0

Answer:

C. 4 2/3

Step-by-step explanation:

1) Use this rule: a/b * c = ac/b.

7 * 6/9

2)  Simplify 7 * 6 to 42.

42/9

3) Simplify.

14/3

4) Convert to mixed fractin form.

4 2/3

lora16 [44]2 years ago
4 0

Answer:

The product of 7/9 and 6:

\\7/9 x 6 \\\\7x6=42\\\\42/9\\4 6/9\\\\4 is the whole number\\6/9 is the fraction that if we remove the 3 from both of us, it gives us the result 2/3\\ The answer is the B \\

Step-by-step explanation:

the answer is the B

Because You only had to multiply 6 by 7 and the result, which would be 42 over 9, should be converted to a mixed number, which would be dividing 42 by 9, which is 4, and us over 6, which is four, which is the whole number, and 6 is the numerator and you don't change the nine since it is still the denominator.

Because the 4 is the whole number

And 6/9 is the fraction that if were move the 3 from both of us , it gives us the result is 2/3

So we have 4 2/3

the answer is the B

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Luda [366]
First, solve the inequality:
7(4x - 1 ) + 6x \ \textgreater \  -279\\
28x-7+6x\ \textgreater \ -279\\
34x\ \textgreater \ -272\\
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Since x is <u>greater than</u> -8, you have the arrow point up the graph towards the positive side starting at -8.
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3 0
3 years ago
Two number cubes are rolled for two separate events:
andrew11 [14]

Answer:  \bold{P(B|A)=\dfrac{P(B\cap A)}{P(A)}=\dfrac{11}{30}}

<u>Step-by-step explanation:</u>

The probability of Event B given Event A = the intersection of Event A and B divided by the probability of Event A. (see below for the symbols)

P(B|A)=\dfrac{P(B\cap A)}{P(A)}

P(A) = (1, 6), (1, 5), (1, 4), (1, 3), (1, 2), (1, 1)

          (2, 6), (2, 5), (2, 4), (2, 3), (2, 2), (2, 1)

          (3, 6), (3, 5), (3, 4), (3, 3), (3, 2), (3, 1)

                    (4, 5), (4, 4), (4, 3), (4, 2), (4, 1)

                              (5, 4), (5, 3), (5, 2), (5, 1)

                                        (6, 3), (6, 2), (6, 1)

       = 30

P(B) = (1, 2), (2, 1)                                   sum = 3

          (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)    sum = 6

          (3, 6), (4, 5), (5, 4), (5, 4), (6, 3)  sum = 9

          (6, 6)                                           sum = 12

                       

      = 12

P(A ∩ B) =  (1, 2), (2, 1)

                  (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)

                  (3, 6), (4, 5), (5, 4), (5, 4), (6, 3)

             = 11

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