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shtirl [24]
3 years ago
13

A human resources department manager is tallying recent statistics regarding the relationship between an applicant being offered

a job and the applicant having a job interview. Of 200 people applying for a job, 10 had an interview. Of those who had an interview, 7 are offered a job. If an applicant was not interviewed, he or she did not have an opportunity to get the job. Fill in the two-way frequency table below.
Job No Job Total

Interview 7 10

No Interview 0

Total 7 200


What is the probability (rounded to the nearest whole percent) that an applicant does not get a job if he or she has an interview? (4 points)


2%

30%

3%

34%
Mathematics
1 answer:
bija089 [108]3 years ago
6 0
I think the paper paper for a copy of the papers that we have to write a copy and copy it in a paper 6765754 paper copy 66456746
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xxTIMURxx [149]

Answer:

critical value = 1.645

The 90% confidence interval = ( -22.62, -17.58)

Step-by-step explanation:

Given that:

the sample  size n_1 = 178

the sample size n_2 = 226

the sample mean \overline x_1 = 54.4

the sample mean \overline x_2 = 74.5

population standard deviation \sigma_1 = 18.58

population standard deviation \sigma_2 = 9.52

level of significance ∝ = 1 - 0.90 = 0.10

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For the construction of our confidence interval, we use 90% since that is used to find the critical value.

∴

The margin of error = Z \times\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}

1.645 \times\sqrt{\dfrac{18.58^2}{178} + \dfrac{9.52^2}{226}}

1.645 \times\sqrt{\dfrac{345.2164}{178} + \dfrac{90.6304}{226}}

1.645 \times\sqrt{2.34042}

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The lower limit = ( \overline x_1 - \overline x_2) - (M.O.E)

= ( 54.4-74.5) - (2.52)

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= -22.62

The upper limit = ( \overline x_1 - \overline x_2) + (M.O.E)

= ( 54.4-74.5) + (2.52)

= -20.1 + 2.52

= -17.58

The 90% confidence interval = ( -22.62, -17.58)

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