Top triangle((6X9)/2)=27square 7x9=63 parallelogram 7X9=69 right triangle ((7X6)/2)=21 so 27+63+63+21=174
40 because 3+6+12 = 21 and 8+11+21 =40
Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
Step-by-step explanation:
We are looking for the value of x so that the function has the given value in the following:
1) h(x) = -7x; h(x)=63
From the function given above,
If h(x) = 63, then,
h(x) = 63 = -7x
-7x = 63
Dividing the left hand side and right hand side of the equation by -7, it becomes
-7x/-7 = 63/-7
x = - 9
2) m(x) = 4x + 15; m(x)=7
From the function given above,
If m(x) = 7, then,
m(x) = 7 = 4x + 15
7 = 4x + 15
4x = 15 - 7 = 8
Dividing the left hand side and right hand side of the equation by 4, it becomes
4x/4 = 8/4
x = 2
3) q(x) = 1/2x - 3; q(x) = -4
From the function given above,
If q(x) = - 4, then,
q(x) = - 4 = 1/(2x - 3) =
Cross multiplying,
-4(2x-3) = 1
-8x +12 = 1
Collecting like terms,
-8x = 1 - 12
-8x = -11
Dividing the left hand side and right hand side of the equation by -8, it becomes
-8x/8 = -11/-8
x = 11/8
Hey smart cookie ;)
So with this all we need to do is factor the expression.
Our answer is going to be 2x(16x^4+15)
Let me know if you have other questions!
Have a terrific day.
~Brooke❤️
