Given:
A circle with diameter 9 cm.
To find:
The area of the circle.
Solution:
The area of a circle is:
...(i)
Where r is the radius.
We know that, the diameter of a circle is twice than its radius.
The diameter of the given circle is 9 cm.
Substituting 
in (i), we get
Therefore, the area of the given circle is 63.6.
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Find the Greatest Common Factor (GCF)
<u>GCF = 6y^6</u>
Factor out the GCF. (Write the GCF first. Then, in parenthesis divide each term by the GCF.)
6y^6(24y^8/6y^6 + 6y^6/6y^6)
Simplify each term in parenthesis
<u>6y^6(4y^2 + 1)</u>
This question is essentially telling you to move the point (5, -2) over three units, and up four units. That means subtract three units from the x-coordinate and add four units to the y-coordinate. So (5 - 3, -2 + 4) --> (2, 2). The coordinates for the new point are (2, 2).
