Graph A since it crosses all 4 regions of the graph
Hey there :)
- tan²x + sec²x = 1 or 1 + tan²x = sec²x
sin²x + cos²x = 1
Divide the whole by cos²x
so
and
so
Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}
1 = - tan²x = sec²x or sec²x - tanx = 1
Answer:
It has none. Angle A is obtuse, so it would have to be opposite the longest side. If side a is opposite angle A, then that is not the case.
Step-by-step explanation:
Answer:
You are drawing a right triangle. So draw the two lines off of the right angle. Then write 5 along one line. That line is now BC, so you can start naming points and putting in lengths. Then, draw the hypotenuse (AB) going from the end of the line you were writing next to, to the other line. Make sure it is at least twice as long, because it is 13 long. Then, to find the length of the last line, square 13, and subtract 25 from it. Take that number and find it's square root. You should get 12, which is your answer.
Step-by-step explanation:
Answer:
3(2) - 5 = 1
Step-by-step explanation:
y = 3x - 5
(x, y)
plug x and y in
1 = 3(2) - 5
1 = 6 - 5
1 = 1
true
