Ask question

Ask question

All categories

3 years ago

5

Anyone know the answer to this??

1 answer:

Mama L [17]3 years ago

7 0

Answer:

I do!

Step-by-step explanation:

You might be interested in

Joshua has a ladder that is 15 feet long. He wants to lean the ladder against a vertical wall so that the top of the ladder is 1

Lyrx [107]

Answer:

Step-by-step explanation:

4 0

2 years ago

About 13% of the population of a large country is nervous around strangersnervous around strangers. If two people are randomly

Molodets [167]

Answer:

1.69% probability both are nervous around strangers.

24.31% probability at least one is nervous around strangers.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are nervous around strangers, or they are not. The people are chosen randomly, which means that the probability of a person being nervous around strangers is independent from other people. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

About 13% of the population of a large country is nervous around strangers.

This means that $p = 0.13$ .

Two people are randomly selected

This means that $n = 2$ .

What is the probability both are nervous around strangers?

This is $P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169$

1.69% probability both are nervous around strangers.

What is the probability at least one is nervous around strangersnervous around strangers?

This is $P(X \geq 1)$

$P(X \geq 1) = P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{2,1}.(0.13)^{1}.(0.87)^{1} = 0.2262$

$P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169$

$P(X \geq 1) = P(X = 1) + P(X = 2) = 0.2262 + 0.0169 = 0.2431$

24.31% probability at least one is nervous around strangers.

3 0

3 years ago

babymother [125]

Answer:

0.36

Step-by-step explanation:

Convert the fraction to a decimal by dividing the numerator by the denominator.

<h3>Hope it is helpful...</h3>

3 0

3 years ago

Read 2 more answers

Vitek1552 [10]

Answer:

the percent is 18

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Rearrange the equation so b is the independent variable 4a+b=−52

Andrej [43]

Answer:

b=-4a-52 or -b=4a+52

Step-by-step explanation:

because you can subtract 4a to the other side or you can subtract 52 to the other side then subtract b to get the second equation.

hope this helps :)

8 0

3 years ago

Read 2 more answers