The answer for your question is C
Answer:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation

For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
Answer:
y=-3x-2
Step-by-step explanation:
step 1- find the slope
parallel to means same slope, so look at y+3x=4, its not in the correct slope form so we subtract both sides by 3x to get y=-3x+4, the slope is the coefficient of x which is -3. Slope equals 3
step 2- use the point slope form which is y-y1=m(x-x1)
and substitute in the numbers (only substitute y1,x1, and m)
m is the slope which we found to equal -3
x1 and y1 are the points that they gave us (-2,4) are (x1,y1)
x1=-2
y1=4
step 3- substitute
y-y1=m(x-x1)
y-4=-3(x-(-2))
simplifies to y-4=-3x-6
add 4 to both sides to get y=-3x-2
Answer:
6
Step-by-step explanation:
450/75= 6 hours