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gayaneshka [121]
3 years ago
7

Jan has $245.50 to spend on home repairs. The repairman charges $75 for the initial visit and $35 per hour or any part of an hou

r. How many hours of work can Jan afford?
Mathematics
1 answer:
Murrr4er [49]3 years ago
4 0

Answer:

4

Step-by-step explanation:

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Help me please come on please.
Alexeev081 [22]
I agree with 11.5 pounds
7 0
3 years ago
An item is regularly priced at $97 . Alonzo bought it at a discount of 85% off the regular price. wats the price now
siniylev [52]

Answer:

at least above 3$

Step-by-step explanation:

5 0
3 years ago
In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.
vodka [1.7K]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

<u>Solution:</u>

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

<em><u>Finding percent of increase in the newspaper’s circulation from 2000 to 2001:</u></em>

\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100

\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}

<em><u>Finding percent of increase in the newspaper’s circulation from 2001 to 2002:</u></em>

\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

7 0
3 years ago
Answer the Blanks:
vfiekz [6]

Answer:

1. 90°

2. 90°

3. 40°

4. 45°

5. 45°

Step-by-step explanation:

<u>Given:</u> ΔABC,

CD⊥AB,

m∠A=50°,

m∠ACB=85°

<u>Solution:</u>

1. ∠ADC is a right ange, because CD⊥AB, so

m\angle ADC=90^{\circ}

2. ∠CDB is a right ange, because CD⊥AB, so

m\angle CDB=90^{\circ}

3. Consider triangle ACD. The sum of the measures of all interior angles is always 180°, so

m\angle A+m\angle ADC+m\angle ACD=180^{\circ}\\ \\50^{\circ}+90^{\circ}+m\angle ACD=180^{\circ}\\ \\m\angle ACD=180^{\circ}-50^{\circ}-90^{\circ}=40^{\circ}

4. By Angle Addition Postulate,

m\angle ACD+m\angle BCD=m\angle ACB\\ \\40^{\circ}+m\angle BCD=85^{\circ}\\ \\m\angle BCD=85^{\circ}-40^{\circ}=45^{\circ}

5. Consider triangle ABC. The sum of the measures of all interior angles is always 180°, so

m\angle A+m\angle ACB+m\angle B=180^{\circ}\\ \\50^{\circ}+85^{\circ}+m\angle B=180^{\circ}\\ \\m\angle B=180^{\circ}-50^{\circ}-85^{\circ}=45^{\circ}

6 0
3 years ago
What is 5 3/20 as a decimal?
Marrrta [24]
5 3/20 = 5.15 <=====
6 0
3 years ago
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