Answer:
at least above 3$
Step-by-step explanation:
Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.
<u>Solution:</u>
Given that,
Total circulation of local newspaper in 2000 = 3250
Total circulation of local newspaper in 2001 = 3640
Total circulation of local newspaper in 2002 = 4100
<em><u>Finding percent of increase in the newspaper’s circulation from 2000 to 2001:</u></em>


<em><u>Finding percent of increase in the newspaper’s circulation from 2001 to 2002:</u></em>

As we can see 12% < 12.6%
So period of 2001 to 2002 has higher increase percentage.
Answer:
1. 90°
2. 90°
3. 40°
4. 45°
5. 45°
Step-by-step explanation:
<u>Given:</u> ΔABC,
CD⊥AB,
m∠A=50°,
m∠ACB=85°
<u>Solution:</u>
1. ∠ADC is a right ange, because CD⊥AB, so

2. ∠CDB is a right ange, because CD⊥AB, so

3. Consider triangle ACD. The sum of the measures of all interior angles is always 180°, so

4. By Angle Addition Postulate,

5. Consider triangle ABC. The sum of the measures of all interior angles is always 180°, so
