Question

What is an equation of the line that passes through the points (-3, -1) and (-6, 3)?

Answer 1

Answer:

y = -4/3x + 2

Step-by-step explanation:

to find slope use m= y2-y1/x2-x1

m= 3-(-1)/-6-(-3)

m= 4/-3

m= -4/3

then use point slope formula (y-y1) =m(x-x1)

(y-(-1)) = -4/3(x-(-3))

simplify

y+1 = -4/3x + 3

turn into slope intercept form

y = -4/3x + 2