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3 years ago

Please help.i am really struggling

Mathematics

1 answer:

alina1380 [7]3 years ago

3 0

Answer:

3,-3) becomes ; (3 + 5 , -3-12) ; (8,-15)

(7,-10) becomes;( 7 + 5, -10-12) ; (12,-22)

(13,-14) becomes (7 + 13, -14-10) ; (20,-24)

Step-by-step explanation:

What we have to do here is to add 5 to the x-axis value and subtract 12 from the y-axis value

(3,-3) becomes ; (3 + 5 , -3-12) ; (8,-15)

(7,-10) becomes;( 7 + 5, -10-12) ; (12,-22)

(13,-14) becomes (7 + 13, -14-10) ; (20,-24)

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Forty - five percent is written in decimal form as 0.45. If 45% of a number is 36 what is the number what is the equation

zvonat [6]

The answer is 80
36/.45=80

8 0

3 years ago

PLZ HURRY IT'S URGENT!!!!!!!!

olga2289 [7]

Let's solve your equation step-by-step.

6+2s−8s=18

Step 1: Simplify both sides of the equation.

6+2s−8s=18

6+2s+−8s=18

(2s+−8s)+(6)=18(Combine Like Terms)

−6s+6=18

Step 2: Subtract 6 from both sides.

−6s+6−6=18−6

−6s=12

Step 3: Divide both sides by -6.

−6s/−6

=12/−6

s=−2

Answer:

s=−2

3 0

4 years ago

Read 2 more answers

Resuelve las siguientes situaciones problemáticas: A) en una caja de 36 naranjas, si se han descompuesto, ¿qué parte del conteni

statuscvo [17]

Answer:

gdjlicnoirfbmlyrsrloydfbm

4 0

3 years ago

Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and th

andrew11 [14]

Answer:

a) 0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b) 0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c) 0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 8.1 minutes and a standard deviation of 2.0 minutes.

This means that $\mu = 8.1, \sigma = 2$

a. between 5 and 10 min

This is the p-value of Z when X = 10 subtracted by the p-value of Z when X = 5.

X = 10

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{10 - 8.1}{2}$

$Z = 0.95$

$Z = 0.95$ has a p-value of 0.8289

X = 5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5 - 8.1}{2}$

$Z = -1.55$

$Z = -1.55$ has a p-value of 0.0606

0.8289 - 0.0606 = 0.7683

0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b. less than 5 min

p-value of Z when X = 5, which, found from item a, is of 0.0606

0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c. more than 10 min

1 subtracted by the p-value of Z when X = 10, which, from item a, is of 0.8289

1 - 0.8289 = 0.1711

0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

7 0

3 years ago

Help!! 30 points!!

erica [24]

Answer:

a. 47.6mph (distance divided by time = speed. divide each rowers distance by their speed, then add them all)

b. 1.26 minutes per mile (i used a calculator so i dunno how to explain)

let me know if this is right or not :)

6 0

3 years ago