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2 years ago

Shawn missed 15% of the problems on his math test if he missed six problems how many problems were on the test

Mathematics

1 answer:

Jlenok [28]2 years ago

6 0

There are 40 questions on the test

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HURRY 20 POINTS!!!!! Given the geometric sequence an = 6(5)n − 1, which of the following values for n lies in the appropriate do

Lapatulllka [165]

<h2>Answer:</h2>

n = 1

<h2>Explanation:</h2>

Here we have the following Geometric Sequence:

$a_{n} = 6(5)^{n-1}$

Where:

$a=6 \ \text{First term} \\ \\ r=5 \ \text{Common ratio} \\ \\ n: \ \text{Number of terms}$

The first term occurs when $n=1$ . Next the second term occurs when $n=2$ , the third term when $n=3$ and so on. Therefore, the appropriate value of n that lies on the domain for n is $n=1$

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3 years ago

A necklace has and matching bracelet have two types of beads. The necklace has 12 large beads and 8 small beads and weighs 88 gr

miv72 [106K]

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Step-by-step explanation:

Let,

Weight of one large bead = x

Weight of one small bead = y

According to given statement;

12x+8y=88 Eqn 1

5x+2y=25 Eqn 2

Multiplying Eqn 2 by 4

$4(5x+2y=25)\\20x+8y=100\ \ \ Eqn\ 3\\$

Subtracting Eqn 1 from Eqn 3

$(20x+8y)-(12x+8y)=100-88\\20x+8y-12x-8y=12\\8x=12$

Dividing both sides by 8

$\frac{8x}{8}=\frac{12}{8}\\x=1.5$

Putting x=1.5 in Eqn 1

$12(1.5)+8y=88\\18+8y=88\\8y=88-18\\8y=70$

Dividing both sides by 8

$\frac{8y}{8}=\frac{70}{8}\\y=8.75$

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

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2 years ago

Prove the identity with steps.

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Remember that a double angle formula for cosine is
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$\rightarrow \cos^{2}(2x)-\sin^{2}(2x)=\cos(2*2x)$
$\rightarrow \cos^{2}(2x)-\sin^{2}(2x)=\cos^{2}(2x)-\sin^{2}(2x)$

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3 years ago

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