What is the period of the function? 1.π 2.2π 3. 3π 4. 4π

How do you turn 9 and 3 5s as a decimal???

Zarrin [17]

Answer:

9.6

Step-by-step explanation:

As 9 and 3/5s, the 9 is whole so you do not change it. To make 3/5th into a decimal you increase the denominator into x/10. To make 5 into 10 you multiply 5x2=10. And since you changed the bottom you have to change the top and multiply it by 2. 3x2=6. So the 9 stays the same and since the first place beind the decimal is tenths, and youre fraction is now 6/10 you put it as 9.6.

Hope it helps!

8 0

3 years ago

For a medical study, a researcher wishes to select people in the middle 60% of the population based on blood pressure.

Finger [1]

Answer:

Lower limit: 113.28

Upper limit: 126.72

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 120, \sigma = 8$

Middle 60%

So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8

Lower limit

X when Z has a pvalue of 0.20. So X when $Z = -0.84$

$Z = \frac{X - \mu}{\sigma}$

$-0.84 = \frac{X - 120}{8}$

$X - 120 = -0.84*8$

$X = 113.28$

Upper limit

X when Z has a pvalue of 0.80. So X when $Z = 0.84$

$Z = \frac{X - \mu}{\sigma}$

$0.84 = \frac{X - 120}{8}$

$X - 120 = 0.84*8$

$X = 126.72$

4 0

3 years ago

There are two formulae you can use to calculate the number of apple trees and the number of conifer

Leno4ka [110]

9514 1404 393

Answer:

n = 8

Step-by-step explanation:

"By inspection" is an appropriate method.

We are asked to compare the expressions

n·n

8·n

and find the value(s) of n that makes them equal. By inspection, we see that n=8 will make these expressions equal. We also know that both expressions will be zero when n=0.

__

More formally, we could write ...

n^2 = 8n . . . . the two formulas give the same value

n^2 -8n = 0 . . . . rearrange to standard form

n(n -8) = 0 . . . . . factor

Using the zero product rule, we know the solutions will be the values of n that make the factors zero. Those values are ...

n = 0 . . . . . makes the factor n = 0

n = 8 . . . . . makes the factor (n-8) = 0

Generally, we're not interested in "trivial" solutions (n=0), so the only value of n that is of interest is n = 8.

__

A lot of times, I find a graphing calculator to be a quick and easy way to find function argument values that make expressions equal.

5 0

3 years ago

What is the equation of the circle with center (1, -1) that passes through the point (5, 7)?

Inessa [10]

Answer:

Equation of the circle =

80 = ( x - 1)^2 + (y + 1)^2

Step-by-step explanation:

Center = (1 , -1)

Point = ( 5 , 7)

Eqn of a circle is

r^2 = (x - h)^2 + (y - k)^2

We are not given the radius of the circle, fortunately we are provided the information that the circle contains a point ( 5, 7), so we use the above information to find r

Using the center (1, -1)

h - 1

k - -1

r^2 = (x - 1)^2 + ( y - -1)^2

r^2 = (x - 1)^2 + (y + 1)^2

With the point ( 5,7)

x = 5

y = 7

r^2 = ( 5 - 1)^2 + ( 7 + 1)^2

= 4^2 + 8^2

= 16 + 64

= 80

r^2 = 80

r = square root of 80

r = 8.94

The r = 8.94 , which means the equation of the circle is

80 = (x - 1)^2 + ( y + 1)^2

5 0

3 years ago

Nter the equation of the line in slope-intercept form. Slope is 6, and (1, 3)

kupik [55]

Answer:

The equation in the slope-intercept form will be:

$y=6x-3$

Step-by-step explanation:

Given

slope = m = 6

point = (1, 3)

As we know that the equation of a line in point-slope form is

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 6 and point = (1, 3)

$y-3=6\left(x-1\right)$

Writing the equation in slope-intercept form

$y=mx+b$

where m is the slope, and b is the y-intercept

so the equation of the line in slope-intercept form becomes

$y-3=6\left(x-1\right)$

add 3 to both sides

$y-3+3=6\left(x-1\right)+3$

$y=6x-3$

Therefore, the equation in the slope-intercept form will be:

$y=6x-3$

6 0

3 years ago