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3 years ago

Compare and contrast the difference between natural numbers and integers

Mathematics

1 answer:

Flura [38]3 years ago

3 0

Answer:

so natural numbers are numbers which of 1... to positive infinity

But when we talk about integers are both positive or negative numbers

either from -1 and above or +1 infinity and above

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José has 3 brown socks, 5 blue socks, and 6 black socks

lukranit [14]

Answer:

independent

Step-by-step explanation:

, it has no effect on the number of red socks so thewhen he draws out a sock the event is not affected by the draw a blue sock or the bla ck sock or the brown sock

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3 years ago

Identify the vertex and axis of symmetry of the graph of g(x) = |x|- 8

Andrews [41]

The vertex is (0,-8)
im not sure about axis of symmetry but i don’t think it has one

7 0

3 years ago

Read 2 more answers

Question :-

DochEvi [55]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's solve ~

$\qquad \sf \dashrightarrow \: \bigg( \dfrac{1}{ \sqrt{7 + \sqrt{5} } } + \sqrt{7 + \sqrt{5} } \bigg) {}^{2}$

$\qquad \sf \dashrightarrow \: \bigg( \dfrac{1}{ \sqrt{7 + \sqrt{5} } } \bigg ) {}^{2} + \bigg( \sqrt{7 + \sqrt{5} } \bigg) {}^{2} + 2 \cdot \dfrac{1}{ \sqrt{7 + \sqrt{5} } } \cdot \sqrt{7 + \sqrt{5} }$

$\qquad \sf \dashrightarrow \: \dfrac{1}{7 + \sqrt{5} } + 7 + \sqrt{5} + 2$

$\qquad \sf \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5} }{7 + \sqrt{5} }$

$\qquad \sf \dashrightarrow \: \dfrac{68+ 16 \sqrt{5} }{7 + \sqrt{5} }$

5 0

2 years ago

What’s the vertex form of F(x)=x^2+2x-3

kupik [55]

Answer:

$\large\boxed{f(x)=(x+1)^2-4}$

Step-by-step explanation:

$\text{The vertex form of a quadratic equation}\ f(x)=ax^2+bx+c:\\\\f(x)=a(x-h)^2+k\\\\(h,\ k)-\text{vertex}\\=====================================$

$\bold{METHOD\ 1:}\\\\\text{convert to the perfect square}\ (a+b)^2=a^2+2ab+b^2\qquad(*)\\\\f(x)=x^2+2x-3=\underbrace{x^2+2(x)(1)+1^2}_{(*)}-1^2-3\\\\f(x)=(x+1)^2-4\\==============================$

$\bold{METHOD\ 2:}\\\\\text{Use the formulas:}\ h=\dfrac{-b}{2a},\ k=f(k)\\\\f(x)=x^2+2x-3\to a=1,\ b=2,\ c=-3\\\\h=\dfrac{-2}{2(1)}=\dfrac{-2}{2}=-1\\\\k=f(-1)=(-1)^2+2(-1)-3=1-2-3=-4\\\\f(x)=(x-(-1))^2-4=(x+1)^2-4$

4 0

4 years ago

Please help me with this...

marusya05 [52]

218 hope this helped

6 0

3 years ago